2 years ago

Twice a number increased by five is 11. What is the number?

Mathematics

1 answer:

Pie2 years ago

7 0

Answer:

Step-by-step explanation:

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2 years ago

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PLEASE HELP!!!!!!!!!

kolezko [41]

Let $x_1 , x_2$ be the roots of the equation $3x^2-5x-7$ . By the Viet theorem you have that $\left \{ {{x_1+x_2=- \frac{5}{3} } \atop {x_1x_2= \frac{-7}{3} }} \right.$ .

For the equation $x^2+bx+c = 0$ you'll have that $c=(x_1+2)(x_2+2)=x_1x_2+2(x_1+x_2)+4=\frac{-7}{3}+2\cdot(- \frac{5}{3} )+4$
That is $\frac{-7}{3}- \frac{10}{3} +4=- \frac{5}{3}$ .

Answer: $- \frac{5}{3}$

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2 years ago