The angle of the plane when it rose from the ground is 64.8 degrees
<h3>Application of trigonometry identity</h3>
Given the following parameters from the question
Altitude of the airplane H = 500m
Horizontal distance from airport "d" = 235
Required
angle of elevation
According to the trigonometry identity
tan x = opposite/adjacent
tan x = H/d
tan x = 500/235
tan x = 2.1277
x = arctan(2.1277)
x = 64.8 degrees
The angle of the plane when it rose from the ground is 64.8 degrees
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Answer: 0.99822
Step-by-step explanation:
Our inter-arrival time follows Poisson distribution with parameter 14 which is in hour so first we have to calculate this in minutes as we have to calculate probability in minutes.
So converting 14 into minutes will give
=0.233
Let X=inter-arrival time between two customers
and here
= 0.233
Probability(X is less than or equal to 2 minutes) = P(X=0) + P(X=1) + P(X=2)
Now the Poisson distribution has PDF =
So P(X = 0) =
= 0.79215
P(X= 1) =
= 0.18457
P(X=2) =
= 0.02150
Now adding all three probability gives = 0.79215 +0.18457 + 0.02150=0.99822
Step-by-step explanation:
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The answer is 50,406
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