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3 years ago

6. Explain a situation in which elastic potential energy could be transformed into kinetic energy.

Chemistry

1 answer:

dsp733 years ago

6 0

Answer:

When you pull a rubber band there is elastic potential energy stored in the rubber band but once you let go of either side the EPE turns into Kinetic Energy.

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Calculate the mass percent composition of sulfur in Al2(SO4)3.

Anastaziya [24]

The molar mass of aluminum sulftae is 342.14 g/mol.

Since the subscript shows that there are 3 sulfurs within the substance, the total mass of sulfur is 96.21g/mol

Now take the mass of the sulfur and divide it by the molar mass of aluminum sulfate, then multiply by 100:
(96.21/342.15)(100) = 28.1% mass composition of sulfate

6 0

3 years ago

2S+3O2 -> 2SO3 Indicate whether S or O2 is the limiting reactant, 3mol S 4mol O, 3mol S 5mol O, 3mol S 3mol? Elemental S reac

Nina [5.8K]

Balanced chemical reaction: 2S + 3O₂ → 2SO₃.

1) Answer is: oxygen is limiting reactant.

n(S) = 3 mol; amount of sulfur.

n(O₂) = 4 mol; amount of oxygen.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

3 mol : n(O₂) = 2 : 3.

n(O₂) = (3 · 3 mol) ÷ 2.

n(O₂) = 4.5 mol; limiting reactant, because there is only 4 mol of oxygen.

2) Answer is: sulfur(S) is limiting reactant.

n(S) = 3 mol.

n(O₂) = 5 mol.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

n(S) : 5 mol = 2 : 3.

n(S) = 10 mol ÷ 3.

n(S) = 3.33 mol; there is only 3 mol of sulfur, so it is not enough.

3) Answer is: oxygen (O₂) is limiting reactant.

n(S) = 3 mol.

n(O₂) = 3 mol.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

3 mol : n(O₂) = 2 : 3.

n(O₂) = (3 · 3 mol) ÷ 2.

n(O₂) = 4.5 mol; limiting reactant, because there is only 3 mol of oxygen.

3 0

4 years ago

Draw the structures of organic compounds a and<br> b. omit all byproducts

Georgia [21]

81. There is 1 carbon, 2 chlorine and fluorine atoms in Freon 12. To draw them it forms a cross with C in the middle and Cl and F both on the opposite side.

8 0

3 years ago

The questions are attached

Sladkaya [172]

Answer:

Explanation:

a) Balanced chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

b) Mass of oxygen gas needed = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of oxygen and propane:

C₃H₈ : O₂

1 : 5

0.57 : 5/1×0.57 = 2.85 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 2.85 mol × 32 g/mol

Mass = 91.2 g

c) water vapors produced = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of water and propane:

C₃H₈ : H₂O

1 : 4

0.57 : 4/1×0.57 = 2.28 mol

Mass of water vapors:

Mass = moles × molar mass

Mass = 2.28 mol × 18 g/mol

Mass = 41.0 g

mass of water vapors produced = 1.5 kg (1500 g)

Mass of propane reacted = ?

Solution:

Number of moles of water vapors:

Number of moles = mass/molar mass

Number of moles = 1500 g/ 18 g/mol

Number of moles = 83.33 mol

now we will compare the moles of water and propane.

H₂O : C₃H₈

4 : 1

83.3 : 1/4×83.3 = 20.8 mol

Mass of propane:

Mass = number of moles ×molar mass

Mass = 20.8 mol × 44.1 g/mol

Mass = 917 g

3 0

3 years ago

A science student observes that a dissolvable antacid tablet acts faster in relieving stomach pain when taken with warm water th

LekaFEV [45]

Answer:the medication would not last as long

Explanation:

Because of the desolving of the tablet so quickly it would

4 0

4 years ago

Read 2 more answers