Answer:
c. To facilitate a reaction of one substrate to form two products without the use of water
Explanation:
A lyase is an enzyme that catalyzes - accelerates the chemical reaction - in which a substrate is broken into two molecules. The reaction does not involve hydrolysis or oxidation, so the water molecule is not included in the chemical reaction. Thus, the enzyme facilitates the reaction in which a molecule (substrate) is decomposed into two molecules with the elimination of chemical bonds.
Answer:
umm ok lol thx for the f r e e points
Answer:
Explanation:
E = hc/λ
h = planck's constant = 6.66 x 10 ^ -34
c = speed of light = 2.98 *10^8 m/s
E = (6.66 x 10 ^ -34 )(2.98 *10^8)/32
= 19.85 * 10 ^-26
=0.62 x 10^-26
= 6.2 x 10^-27 J
Answer:
Constant pressure
Explanation:
At constant pressure,

At constant temperature,

1 mol of an ideal gas at STP has a volume of 22.71 L.
Let's compare the work done as it expands under each condition from an initial volume of 22.71 L.
Isobaric expansion

A plot of -w vs V₂ gives a straight line (red) with a constant slope of 100 J/L as in the diagram below (Note that w is work done on the system, so -w is the work done by the system).
\
Isothermal expansion

A plot of -w vs V₂ is a logarithmic curve. Its slope starts at 100 J/mol but decreases as the volume increases (the blue curve below).
Thus, the work done during an expansion at constant pressure is greater than if the system is at constant temperature.