Answer:
32.7 L of H₂
Explanation:
We'll begin by calculating the number of mole in 95 g of Zn. This can be obtained as follow:
Mass of Zn = 95 g
Molar mass of Zn = 65 g/mol
Mole of Zn =?
Mole = mass /Molar mass
Mole of Zn = 95/65
Mole of Zn = 1.46 mole
Next, we shall determine the number of mole of H₂ produced by the reaction of 95 g (i.e 1.46 mole) of Zn. This can be obtained as illustrated below:
Zn + H₂SO₄ —> ZnSO₄ + H₂
From the balanced equation above,
1 mole of Zn reacted to produce 1 mole of H₂.
Therefore, 1.46 mole of Zn will also react to produce 1.46 mole of H₂.
Finally, we shall determine the volume of H₂ obtained at STP. This can be obtained as follow:
1 mole of H₂ = 22.4 L at STP.
Therefore,
1.46 mole of H₂ = 1.46 × 22.4
1.46 mole of H₂ = 32.7 L at STP
Thus, 32.7 L of H₂ were obtained from the reaction.
Answer:
Explanation:
1 mol of sodium = 23 grams (use the number on your periodic table).
0.7350 mol sodium = x
Cross multiply
1*x = 0.7350 * 23
x = 16.905
You will get slightly less than this, depending on your periodic table. But the method will be the same.
Answer:
Well what are the numbers but ik that it ius 5
Explanation:
Hello,
You balanced the equation and then you have to set up what is called a psychometric equation for each reactant so that you get the same unit for each in order to compare the two. so for (calcium hydroxide) = 78.5 g ÷ (40.1 + 32 + 2) = 1.0593 mol * Note: I just broke it down in my own science way..u can just get the molar mass of calcium hydroxide which is approx 74 g/mol
Hope this helps