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kap26 [50]
2 years ago
9

After transferring the electron, which ion is negatively charged? ________________ Why is the ion negatively charged? __________

________________________ Write the symbol for the negative ion: __________________________________-
Chemistry
1 answer:
pychu [463]2 years ago
7 0

After transferring an electron, the ion that lost an electron, assuming it was neutral before, would be a cation. The atom that gained an electron would be an anion.

The ion is negatively charged because it has gained an ion, adding a negative charge to the atom's neutral state. Because it has no protons to cancel the charge, it gains 1 negative charge, making it an anion.

The symbol for a negative ion would be (-) and a positive would be (+)

For example, when oxygen is an ion, here's how it would look: O2-

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Which of the following is an example of a chemical change?
wolverine [178]

Answer:

C

Explanation:

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2 years ago
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Draw and label the parts of a helium atom. Include the mass and charge of each subatomic particle.
mihalych1998 [28]

Explanation:

Helium is the second element on the periodic table.

  Information about helium:

  • it belongs to group O on the periodic table
  • it is has an atomic number of 2
  • Helium exists naturally as gas and it is nonreactive.

  To write an atom we use this format:

                                     ₙᵇGˣ

   G is the symbol of the atom

   n is the atomic number  

   b is the mass number

    x is the charge on the atom

Using the periodic table as guide

    Symbol of helium is He

     Atomic number of helium is 2

     mass number of helium is 4

     charge on helium atom is 0

                              ⁴₂He

Every atom contains protons, neutrons and electrons;

   Electrons are negatively charged. For a neutral atom, the number of electrons is the same as that of protons.

   Protons are positively charge particles in an atom. The atomic number is the number of protons in an atom.

   neutrons do not have charges.

 

   Helium has:

        Number of protons = 2

        Number of electrons = 2

        Number of neutrons = 2

Mass of each subatomic particle:

      1 electron = 9.11 x 10⁻³¹kg

      2 electrons = 1.82 x 10⁻³⁰kg  

     Protons and neutrons have the same mass:

           1 proton = 1.67 x 10⁻²⁷kg

           2 protons = 3.34 x 10⁻²⁷kg

           2 neutrons = 3.34 x 10⁻²⁷kg

Learn more:

helium brainly.com/question/2439349

#learnwithBrainly

4 0
3 years ago
What is the value for the reaction: N2(g) + 2 O2(g) --> N2O4(g) in terms of K values from the reactions:
Valentin [98]

Answer : The correct expression will be:

K=(K_1)^2\times K_2

Explanation :

The chemical reactions are :

(1) \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g) K_1

(2) 2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g) K_2

The final chemical reaction is :

N_2(g)+2O_2(g)\rightleftharpoons N_2O_4 K=?

Now we have to calculate the value of K for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

K=(K_1)^2\times K_2

6 0
3 years ago
What are crayons made of?
Mashutka [201]
They are made of different color of waxes

7 0
3 years ago
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You need to prepare at 2.0 mL sample of a diluted drug for injection. The total amount of the drug to be injected in this 2.0 mL
pav-90 [236]

Answer:

a) The concentration of drug in the bottle is 9.8 mg/ml

b) 0.15 ml drug solution + 1.85 ml saline.

c) 4.9 × 10⁻⁵ mol/l

Explanation:

Hi there!

a) The concentration of the drug in the bottle is 294 mg/ 30.0 ml = 9.8 mg/ml

b) The drug has to be administrated at a dose of 0.0210 mg/ kg body mass. Then, the total mass of drug that there should be in the injection for a person of 70 kg will be:

0.0210 mg/kg-body mass * 70 kg = 1.47 mg drug.

The volume of solution that contains that mass of drug can be calculated using the value of the concentration calculated in a)

If 9.8 mg of the drug is contained in 1 ml of solution, then 1.47 mg drug will be present in (1.47 mg * 1 ml/ 9.8 mg) 0.15 ml.

To prepare the injection, you should take 0.15 ml of the concentrated drug solution and (2.0 ml - 0.15 ml) 1.85 ml saline

c) In the injection there is a concentration of (1.47 mg / 2.0 ml) 0.735 mg/ml.

Let´s convert it to molarity:

0.735 mg/ml * 1000 ml/l * 0.001 g/mg* 1 mol/ 15000 g = 4.9 × 10⁻⁵ mol/l

3 0
3 years ago
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