Answer:
80g
Explanation:
2H2 + O2 —> 2H2O
MM of H2O = (2x1) + 16 = 2 + 16 = 18g/mol
Mass conc. of H2O from the balanced equation = 2 x 18 = 36g
MM of O2 = 16 x 2 = 32g/mol
From the equation,
32g of O2 reacted to produce 36g of H2O.
Therefore Xg of O2 will react to produce 90g of H2O i.e
Xg of O2 = (32x90)/36 = 80g
Answer:
Explanation:
Diameter in the coin is the distance from side to side.
The numbers in the ruler are showing the centimeters. Each line is a subdivision in ten parts between centimeter and centimeter (Each line is equal to 1mm).
As you can see in the ruler, in the edge of the coin, the ruler is showing 3.8cm
As 1cm = 10mm:
3.8cm * (10mm / 1cm) =
38mm is the diameter of the coin to the nearest milimeter
The formula for determination of atomic mass given the mass of isotopes and relative abundance is:
Ar = ∑(mass * abundance) / 100
Ar = (68.92558 * 60.108 + 70.92470 * 39.892) / 100
Ar = 69.72306
The atomic mass of gallium is 69.72306 amu
Answer:
Potassium = 4s¹
Carbon = 2p²
Sulfur = 3p⁴
Barium = 6s²
Xenon = 5p⁶
Explanation:
1) Potassium is present in group one.
Its electronic configuration is:
K = [Ar] 4s¹
So its highest energy electrons are 4s¹.
2) Carbon is present in group 14.
Its electronic configuration is:
C = [He] 2s² 2p²
So its highest energy electrons are 2p².
3) Sulfur is present in group 16.
Its electronic configuration is:
S = [Ar] 3s² 3p⁴
So its highest energy electrons are 3p⁴.
4) Barium is present in group 2.
Its electronic configuration is:
Ba = [Xe] 6s²
So its highest energy electrons are 6s² .
5) Xenon is present in group 18.
Its electronic configuration is:
Xe= [Kr] 4d¹⁰ 5s² 5p⁶
So its highest energy electrons are 5p⁶
