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2 years ago

How many moles are in 987 grams of : Ra(OH)2

Chemistry

2 answers:

sergejj [24]2 years ago

8 0

Your answer is 3.80 moles

likoan [24]2 years ago

6 0

Here are the molar masses of these atoms:

Ra = 226 g/mol

H = 1.008 g/mol * 2 (there are two hydrogen atoms in radium hydroxide)

O = 15.999 g/mol * 2

The molar mass of radium hydroxide is therefore 260.014 g/mol.

Divide this number by 987 grams to cancel the units in order to obtain the number moles.

260.014 g/mol / 987 g = 0.263 mol

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graduated cylinder is filled with water to a volume of 6.2 ML. an irregular shaped plastic object weighing 1.2 g is placed in th

Aleks04 [339]

Answer:

A. Density of object = 0.86 g/mL

B. The object will float in the water.

Explanation:

The following data were obtained from the question:

Volume of water = 6.2 mL

Mass (m) of object = 1.2 g

Volume of water + Object = 7.59 mL

Density of object =?

Density of water = 1 g/mL

Next, we shall determine the volume of the object. This can be obtained as follow:

Volume of water = 6.2 mL

Volume of water + Object = 7.59 mL

Volume of object =?

Volume of object = (Volume of water + Object) – (Volume of water)

Volume of object = 7.59 – 6.2

Volume of object = 1.39 mL

Therefore, the volume of the object is 1.39 mL

A. Determination of the density of the object.

Mass (m) of object = 1.2 g

Volume (V) of object = 1.39 mL

Density (D) of object =?

Density = mass /volume

Density = 1.2/1.39

Density of object = 0.86 g/mL

B. Determination of whether the object will float or sink.

Density of object = 0.86 g/mL

Density of water = 1 g/mL

From the above, we can see that the density of water is greater than that of the object. This implies that the object is lighter than water. Therefore, the object will float in the water.

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ryzh [129]

Answer:

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Aleksandr [31]

Answer:

B) Symmetrical and nonpolar

Step-by-step explanation:

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Kruka [31]

Answer:

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