All categories

3 years ago

How are cellular respiration and photosynthesis related?

Chemistry

1 answer:

jekas [21]3 years ago

3 0

Answer:

Explanation:

Hope it helps

 #CarryOnLearning 

You might be interested in

In a balanced chemical equation,

Wewaii [24]

Answer:

The Answer is A

Explanation:

Please let me know if I am wrong

8 0

3 years ago

Read 2 more answers

Which of the following is likely to have the lowest viscosity? hot oil room temperature oil room temperature water below room te

zzz [600]

Viscosity, is a state of matter where it resists flow or may be in thick semifluid form because of friction acting inside the matter.In this case, hot oil room temperature would lessen the viscosity of the oil (animal oil). Thank you for your question. Please don't hesitate to ask in Brainly your queries.

4 0

4 years ago

Read 2 more answers

Suppose you have a 0.10 M solution of AlBr3. What is the concentration of each ion? A. 0.10 M Al3+ ions and 0.30 M Br- ions B. 0

podryga [215]

Answer: The concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M

Explanation:

We are given:

Concentration of $AlBr_3$ = 0.10 M

The chemical equation for the ionization of aluminium bromide follows:

$AlBr_3\rightarrow Al^{3+}+3Br^-$

1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions

So, concentration of aluminium ions = 0.10 M

Concentration of bromide ions = $[(3\times 0.1)]=0.3M$

Hence, the concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M

8 0

3 years ago

The Henry's law constant (kH) for O2 in water at 20°C is 1.28e-3 mol/l atm. How many grams of O2 will dissolve in 3.5 L of H2O t

Sophie [7]

Answer : The mass of $O_2$ dissolved will be, 0.2365 grams

Explanation :

First we have to calculate the concentration of $O_2$ .

As we know that,

$C_{O_2}=k_H\times p_{O_2}$

where,

$C_{O_2}$ = concentration of $O_2$ = ?

$p_{O_2}$ = partial pressure of $O_2$ = 1.65 atm

$k_H$ = Henry's law constant = $1.28\times 10^{-3}mole/L.atm$

Now put all the given values in the above formula, we get:

$C_{O_2}=(1.28\times 10^{-3}mole/L.atm)\times (1.65atm)$

$C_{O_2}=2.112\times 10^{-3}mole/L$

The concentration of $O_2$ = $2.112\times 10^{-3}mole/L$

Now we have to calculate the moles of $O_2$

$\text{Moles of }O_2=\text{Concentration of }O_2\times \text{volume of solution}$

$\text{Moles of }O_2=(2.112\times 10^{-3}mole/L)\times (3.5L)=7.392\times 10^{-3}mole$

Now we have to calculate the mass of $O_2$

$\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2$

$\text{Mass of }O_2=(7.392\times 10^{-3}mole)\times (32g/mole)=0.2365g$

Therefore, the mass of $O_2$ dissolved will be, 0.2365 grams

4 0

3 years ago

The formation of large molecules from small repeating units is known as what kind of reaction? Oxidation reduction condensation

natka813 [3]

Answer:

The formation of large molecules from small repeating units is known as Condensation reactions.

Explanation:

Those reactions in which two molecules join together with a elimination of small neutral molecule like H₂O, CH₃OH, HCl e.t.c are known as condensation reactions.

Polymerization reactions are those reactions in which small molecules called as monomers join together to form a large molecule also known as polymers. These reactions are done via different mechanisms among which one is the condensation reaction.

Example:

Proteins (polymer) are made up of amino acids (monomers) through condensation reaction as,

n H₂N-RH-COOH → H₂N-[-RH]n-COOH + n H₂O

In above equation "n" represent large number, H₂N-RH-COOH represent amino acid (monomer) and H₂N-[-RH]n-COOH represent protein (polymer). While, the H₂O eliminated is the small neutral molecule.

7 0

3 years ago