Please write the answer in format below

Chemistry

1 answer:

jeyben [28]3 years ago

4 0

Answer:

0.95 L

Explanation:

Step 1: Given data

Concentration of the Mg(NO₃)₂ solution (C): 0.32 M (0.32 mol/L)

Mass of Mg(NO₃)₂ (solute): 45 g

Step 2: Calculate the moles corresponding to 45 g of Mg(NO₃)₂

The molar mass of Mg(NO₃)₂ is 148.33 g/mol.

45 g Mg(NO₃)₂ × 1 mol Mg(NO₃)₂ /148.33 g Mg(NO₃)₂ = 0.303 mol Mg(NO₃)₂

Step 3: Calculate the volume of solution that contains 0.303 moles of Mg(NO₃)₂

The concentration of the solution is 0.32 M, that is, there are 0.32 moles of Mg(NO₃)₂ per liter of solution.

0.303 mol Mg(NO₃)₂ × 1 L Solution / 0.32 mol Mg(NO₃)₂ = 0.95 L

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