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Kay [80]
2 years ago
10

How many moles of C5H120 would it take to generate 4.2 moles of CO2 from combustion?

Chemistry
1 answer:
dalvyx [7]2 years ago
3 0

Answer:

0.84 moles

Explanation:

from the equation 2 moles of pentanol generated 10 moles of CO2 therefore, x mol of pentanol will generate 4.2mol of CO2.

making x the subject of formula=4.2*2/10

=0.84 moles of

pentanol

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If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and
julia-pushkina [17]

Answer:

V₂ = 0.95 L

Explanation:

Given data:

Initial temperature of gas = 171.4 K

Final temperature of gas = 288.4 K

Final volume = 1.6 L

Initial volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₂ = 1.6 L × 171.4 K / 288.4 k

V₂ = 274.24 L.K / 288.4 K

V₂ = 0.95 L

6 0
3 years ago
Octane has a density of 0.692 g/ml at 20∘c. how many grams of o2 are required to burn 17.0 gal of c8h18
german

156251.099 grams of O₂ are required to burn 17.0 gal of C₈H₁₈

<h3>Further explanation</h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g / cm³ or kg / m³

Density formula:

\large{\boxed{\bold{\rho~=~\frac{m}{V} }}}

ρ = density

m = mass

v = volume

1 gal equal to = 3785.41 ml

then 17.0 gal = 17 x 3785.41 = 64351.97 ml Octane

grams Octane = ρ x ml

grams Octane = 0.692 g.ml x 64351.97

grams Octane = 44531.563

molar mass Octane (C₈H₁₈) = 114

mole Octane = grams : molar mass

mole Octane = 44531.563  : 114

mole Octane = 390.627

From the reaction

C₈H₁₈ + 25/2 O₂ ⇒ 8 CO₂ + 9H₂O

mole C₈H₁₈ : mole O₂ = 1 : 25/2

mole\:O_2\:=\:\frac{25}{2} \times\:390.627

mole O₂ = 4882.846

grams O₂ = mole x molar mass

grams O₂ = 4882.846 x 32

grams O₂ = 156251.099

<h3>Learn more </h3>

moles of water

brainly.com/question/1405182

grams of oxygen required

brainly.com/question/8175791

mass of copper required

brainly.com/question/1680090

Keywords: Octane,  mole, mass, gal, density

5 0
3 years ago
Please help don’t understand this I attached the question
Rasek [7]

Answer:

58.32

Explanation:

The mass number is one mole and for Mg it is 24.306 for O it is 15.999 and for H it is 1.008. because O and H have 2, you multiply them by 2 and add all the numbers and it equals 58.32

8 0
1 year ago
Read 2 more answers
Choose all the answers that apply.
Arada [10]

Answer:

removing topsoil

Explanation:

5 0
2 years ago
Read 2 more answers
Pls help name any of these compounds​
Eva8 [605]

Answer:

D. Propanol

Explanation:

C3H7OH the presence of alcohol functional group makes it propanol

3 0
2 years ago
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