Answer is: the approximate freezing point of a 0.10 m NaCl solution is -2x°C.
V<span>an't
Hoff factor (i) for NaCl solution is approximately 2.
</span>Van't Hoff factor (i) for glucose solution is 1.<span>
Change in freezing point from pure solvent to
solution: ΔT = i · Kf · m.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
m - molality, moles of solute per
kilogram of solvent.
</span>Kf and molality for this two solutions are the same, but Van't Hoff factor for sodium chloride is twice bigger, so freezing point is twice bigger.
The error is in the formula is bracket so the correct is Mg(OH)₂
The incorrect or error in the formula is bracket that would be that the compound contain only 1Mg atom and 1 oxygen atom and 2 hydrogen atom but is wrong when you write it in an electron dot diagram you will see that it is wrong there be unshared paired of electron and the correct formula is Mg(OH)₂
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Answer:
The description of the given question is summarized in the explanation section below.
Explanation:
A maximum of around 82 ppm would be found throughout the beginning material spectrum around CDCl3. This same resulting spectrum maximum of 82 ppm has been lost, as well as the section has a historic high of 215 ppm.
- The OH summit at 82 ppm was obvious as well as a significant maximum of around 215 ppm carboxylic acid was observed.
- That justifies the occurrence of oxidizing, C13 NMR was indeed verified as a reactive organic compound oxidized in carbonyl Ozone.
Answer:
h = 0.346 m
Explanation:
mercury barometer:
∴ Pa = 0.455 atm = 46102.875 Pa = 46102.875 Kg/ms²
∴ ρ = 13600 Kg/m³
∴ g = 9.80 m/s²
⇒ h = (46102.875 Kg/ms²) / (13600 Kg/m³ )(9.80 m/s²)
⇒ h = 0.346 m
I believe the answer is S^2 or 0
