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laiz [17]
3 years ago
7

A 4.5-liter sample of a gas has 0.80 mole of the gas. If 0.35 mole of the gas is added, what is the final volume of the gas? Tem

perature and pressure remain constant.
3.9 liters
5.3 liters
6.3 liters
6.5 liters
Chemistry
2 answers:
zzz [600]3 years ago
6 0

Answer:

6.5 L

Explanation:

Given: 0.80 mol in 4.5 L

Find: x liters containing (0.80 mol + 0.35 mol)

Solve: 0.80 mol/4.5 L = (0.80 mol + 0.35 mol)/ x

0.80 mol/ 4.5 L = (1.15 mol) /x

x = (1.15 mol)(4.5L)/(0.80 mol)

x = 6.47 L = 6.5 L

AVprozaik [17]3 years ago
5 0

Answer:

6.5 liters will be your answer

Explanation:

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Answer:

A. is the correct point.

Explanation:

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4 0
3 years ago
How many grams of dry nh4cl need to be added to 2.50 l of a 0.800 m solution of ammonia, nh3, to prepare a buffer solution that
tia_tia [17]

Answer:

The correct answer is 574.59 grams.

Explanation:

Based on the given information, the number of moles of NH₃ will be,  

= 2.50 L × 0.800 mol/L

= 2 mol

The given pH of a buffer is 8.53

pH + pOH = 14.00

pOH = 14.00 - pH

pOH = 14.00 - 8.53

pOH = 5.47

The Kb of ammonia given is 1.8 * 10^-5. Now pKb = -logKb,  

= -log (1.8 ×10⁻⁵)

= 5.00 - log 1.8

= 5.00 - 0.26

= 4.74

Based on Henderson equation:  

pOH = pKb + log ([salt]/[base])

pOH = pKb + [NH₄⁺]/[NH₃]

5.47 = 4.74 + log ([NH₄⁺]/[NH₃])

log([NH₄⁺]/[NH₃]) = 5.47-4.74 = 0.73

[NH₄⁺]/[NH₃] = 10^0.73= 5.37

[NH₄⁺ = 5.37 × 2 mol = 10.74 mol

Now the mass of dry ammonium chloride required is,  

mass of NH₄Cl = 10.74 mol × 53.5 g/mol

= 574.59 grams.  

8 0
3 years ago
What happens to the ph of the reaction mixture as the oxidation reaction proceeds in an oxidation of an aromatic side chain?
andrew11 [14]

Answer:

The pH decreases.

Explanation:

Hello,

In organic chemistry, oxidation accounts for either the increasing of C-O bonds or the increasing in the oxygen atoms into the molecule. Thus, if we consider the oxidation from benzyl alcohol to benzoic acid, there will be a carboxyl functional group instead of a hydroxile one. Now, the presence of the polar -O-H bonds that are ionizable, there will be a H^{+1} releasing causing the pH to decrease (increase acidity).

Regards.

4 0
3 years ago
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