Answer:
None of the above
Explanation:
The (−OH) group on phenol can form hydrogen bonds, and the −CH3 group on toluene cannot.
Phenol has only one hydrogen on the −OH group available to form hydrogen bonds, so the hydrogen bond is stronger. In toluene, the hydrogen bond is spread over all three hydrogens on the methyl group, so the interaction is weaker overall.
Phenol has a higher molecular mass than toluene.
1. 842g of NaOH will form 547.3 g of Al(OH)₃
2. The yield is 93.55%
<u>Explanation:</u>
3NaOH + Al → Al(OH)₃ + 3Na
1.
Molar mass of NaOH = 40 g/mol
Molar mass of Al = 27 g/mol
Molar mass of Al(OH)₃ = 78 g/mol
According to the balanced equation:
3 moles of NaOH requires 1 mole of Al to form 1 mole of Al(OH)₃
The ratio of NaOH : Al : Al(OH)₃ = 3 : 1 : 1
3 X 40 g of NaOH reacts with 27 g of Al to form 78 g of Al(OH)₃
120 g of NaOH + 27g of Al → 78 g of Al(OH)₃
120g of NaOH form 78g of Al(OH)₃
1g of NaOH will form
g of Al(OH)₃
842g of NaOH will form
of Al(OH)₃
= 547.3 g of Al(OH)₃
Therefore, 842g of NaOH will form 547.3 g of Al(OH)₃
2. Only 512 g of Al(OH)₃ is formed
Yield % = ?

Therefore, the yield is 93.55%
Answer: 2 moles of water.
Explanation:

Given moles:
moles of oxygen = 2.5
moles of
= 4.6
According to stoichiometry:
5 moles of oxygen reacts with = 1 mole of propane
Thus 2.5 moles of oxygen will react with =
moles of oxygen
Thus propane is the limiting reagent as it limits the formation of products and oxygen is the excess reagent.
As 1 mole of propane produce = 4 moles of water
0.5 mole of propane will produce =
of water
Thus 2 moles of water are produced.
He would hv concluded that the ratio of the masses of nitrogen to sulphur is in the ratio 1 :3
Atomic Theory. In 1897, English physicist J. J. Thomson (1856–1940) disproved Dalton's idea that atoms are indivisible. ... One of those parts is a negative tiny particle, which Thomson called a corpuscle in 1881.
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