When metals combine with non metals , the metallic atom tend to
1 answer:
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1. 842g of NaOH will form 547.3 g of Al(OH)₃
2. The yield is 93.55%
<u>Explanation:</u>
3NaOH + Al → Al(OH)₃ + 3Na
1.
Molar mass of NaOH = 40 g/mol
Molar mass of Al = 27 g/mol
Molar mass of Al(OH)₃ = 78 g/mol
According to the balanced equation:
3 moles of NaOH requires 1 mole of Al to form 1 mole of Al(OH)₃
The ratio of NaOH : Al : Al(OH)₃ = 3 : 1 : 1
3 X 40 g of NaOH reacts with 27 g of Al to form 78 g of Al(OH)₃
120 g of NaOH + 27g of Al → 78 g of Al(OH)₃
120g of NaOH form 78g of Al(OH)₃
1g of NaOH will form g of Al(OH)₃
842g of NaOH will form of Al(OH)₃
= 547.3 g of Al(OH)₃
Therefore, 842g of NaOH will form 547.3 g of Al(OH)₃
2. Only 512 g of Al(OH)₃ is formed
Yield % = ?
Therefore, the yield is 93.55%
Answer: 2 moles of water.
Explanation:
Given moles:
moles of oxygen = 2.5
moles of = 4.6
According to stoichiometry:
5 moles of oxygen reacts with = 1 mole of propane
Thus 2.5 moles of oxygen will react with = moles of oxygen
Thus propane is the limiting reagent as it limits the formation of products and oxygen is the excess reagent.
As 1 mole of propane produce = 4 moles of water
0.5 mole of propane will produce = of water
Thus 2 moles of water are produced.