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Anna35 [415]
3 years ago
15

Which best describes oogenesis?​

Chemistry
1 answer:
kkurt [141]3 years ago
6 0

Explanation:

Oogenesis can be defined as a process of differentiation of egg cell (ovum), into a mature ovum that further develops after fertilization. In humans, oogenesis begins in the early stage of embryonic development, during whcih primary oocyte performs meiosis I and forms secondary oocyte.

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Solid Silicon can be reacted with Nitrogen gas at a high temperature to form silicon nitride (Si3N4).
slamgirl [31]
Solid Silicon can be reacted with Nitrogen gas at a high temperature to form silicon nitride (Si3N4).
1.20 moles of Silicon are added to 1.00 moles of Nitrogen gas.
(5 Points) Balance the equation and indicate the phases.

Si (___) + N2 (___) → Si3N4 (___)

(5 Points) What is the limiting reactant? You must show your work.
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3 years ago
A particular chemical reaction absorbs energy. It is possible to say the reactants possessed a lower energy than the products. T
Harrizon [31]

i'm pretty sure its true
5 0
3 years ago
Read 2 more answers
Which of the following statement(s) is/are TRUE for the citric acid titration?
RoseWind [281]

Under-titrating means too little indicator was added to the reaction.

TRUE

Since the volume of titrant is too small, multiplying by a small number in the calculation of citric acid makes the mass of citric acid too low.

TRUE

The reaction was stopped too quickly (before reaction was complete).

FALSE

3 0
4 years ago
PLEASE HELP!! GIVING BRAINLIEST
RSB [31]

Answer:

The answer is "0.00172172603".

Explanation:

Given:

Mass (M) = 1.60 \times  10^{-3} \ g\\\\Density (D) = 9.293 \times 10^{-1} \ \frac{g}{cm^3}\\\\Volume (V) =  ?

Formula:

\to \bold{V = \frac{M}{D}}

       = \frac{1.60 \times  10^{-3}}{9.293 \times  10^{-1}} \\\\  = \frac{1.60 \times  10^{1}}{9.293 \times  10^{3}} \\\\ = \frac{1.60 \times  10}{9.293 \times  1000} \\\\ = \frac{1.60 }{9.293 \times  100} \\\\ = \frac{1.60 }{929.3 } \\\\= 0.00172172603

4 0
3 years ago
Animal Reproduction Interactivity
Leviafan [203]

<u>Step</u><u> </u><u>1</u>

Jellyfish do not give birth to their young because they expel undeveloped eggs in the form of zygote or embryo from their bodies and deposit them on the ocean floor before moving on. They don't even care about the eggs that have been laid.

<u>Step</u><u> </u><u>2</u>

Jellyfish have two distinct body types during their lives: medusa and polyps. Polyps reproduce by budding while medusa reproduce as by spawning eggs and sperm.

Jellyfish can reproduce in the adult, or medusa, stage by releasing sperm and eggs into the water, forming a planula. Polyps clone themselves and bud, or strobilate, into ephyra, a different stage of jellyfish life. The adult medusa jellyfish develops from his form.

Only a few jellyfish species obtain sperm through their mouths in order to fertilise eggs within their bodies, but the majority of jellyfish simply release sperm or eggs into the water. They will do this once a day, normally at dawn or dusk, if conditions are favorable.

4 0
3 years ago
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