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Naddik [55]
3 years ago
13

What is the reduction half-reaction for 2Mg + O2 → 2Mgo?

Chemistry
1 answer:
Helen [10]3 years ago
4 0

Answer:

When magnesium burns, it combines with oxygen (O2) from the air to form magnesium oxide (MgO) according to the following equation: 2Mg(s) + O2(g) → 2MgO(s) ... Thus, a reduction half reaction can be written for the O2 as it gains 4 electrons: O2(g) + 4e− → 2O.

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What was the Copernican revolution?
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4 0
2 years ago
4. How many J of energy are needed to raise the temperature of 165 g of water from 10.55°C to 47.32°C?
jeka94

Answer:

Q = 25360.269 j

Explanation:

Given data:

Mass = 165 g

Initial temperature = 10.55 °C

Final temperature = 47.32°C

Energy absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2 - T1

ΔT  = 47.32°C - 10.55 °C

ΔT  = 36.77 °C

Q = m.c. ΔT

Q = 165 g . 4.18 j/g.°C . 36.77 °C

Q = 25360.269 j

3 0
3 years ago
The combustion reaction of c3h8o with o2 is represented by this balanced chemical equation. 2c3h8o + 9o2 6co2 + 8h2o when 3.00 g
MArishka [77]
<span>According to the question- 1 mol C3H8O = 60.096 g C3H8O 2 mol C3H8O = 9 mol O2 1 mol O2 = 31.998 g O2 [(3.00 g C3H8O)/1][(1 mol C3H8O)/(60.096)][(9 mol O2)/(2 mol C3H8O)][(32.998 g O2)/(1 mol O2)] = 7.1880435 g O2 Since 7.1880435 g of O2 is needed, and 7.38 g of O2 is available, 0.199565 g of O2 will be left over and oxygen is present in excess. Next, we need to convert 0.199565 g of O2 into moles of O2: [(0.199565 g O2)/1][(1 mol O2)/(31.998 g O2)] = 0.005999 mol O2, or 0.006 mol O2</span>
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3 years ago
How many significant figures are in 0.00326
mina [271]
There are 3 significant figures.
5 0
3 years ago
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