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ahrayia [7]
4 years ago
7

A car travels 66 kilometers in 3 hours. what is its speed

Chemistry
2 answers:
Ne4ueva [31]4 years ago
8 0

Answer:

22 kph

Explanation:

You simply divide the distance and the time. 66/3 = 22.

Elza [17]4 years ago
4 0
Answer:

Speed = 22 km/h

Explanation:

The equation to calculate speed is as follows:

Speed = distance/time

Since we are given distance and time, all we have to do is plug these values into our formula.

Speed = 66 km / 3 h

Speed = 22 km/h
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Firdavs [7]
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3 0
4 years ago
The name given to the Earth's climate when there was no ice at the poles
Citrus2011 [14]

Answer:

i think snowball, it sounds weird but its true (i think im sorry if its wrong)

Explanation:

7 0
3 years ago
Can someone help me
Sphinxa [80]

Answer: 0.24

Explanation:

M=\frac{moles}{L}\\ M=\frac{0.6 moles}{2.5L} \\M=0.24

4 0
3 years ago
The equilibrium constant for the reaction
FinnZ [79.3K]

Answer: The concentrations of Cl_2 at equilibrium is 0.023 M

Explanation:

Moles of  Cl_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol

Volume of solution = 1 L

Initial concentration of Cl_2 = \frac{0.14mol}{1L}=0.14M

The given balanced equilibrium reaction is,

                            COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial conc.           0.14 M           0 M       0M    

At eqm. conc.     (0.14-x) M        (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}

Now put all the given values in this expression, we get :

4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of Cl_2 at equilibrium is 0.023 M

7 0
3 years ago
Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what
kozerog [31]

Answer: 300 K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles)

V=kT

Given : V= 6.0 L

k= 0.020 L/K

T=?

6.0=0.020LK^{-1}\times T

T=300 K

Thus temperature of the gas is 300 K.

3 0
3 years ago
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