The number of Ml of a 0.40 %w/v solution of ,nalorphine that must be injected to obtain a dose of 1.5 mg is calculated as below
since M/v% is mass of solute in grams per 100 ml
convert Mg to g
1 g = 1000 mg what about 1.5 mg =? grams
= 1.5 /1000 = 0.0015 grams
volume is therefore = 100 ( mass/ M/v%)
= 100 x( 0.0015/ 0.4) = 0.375 ML
dissolves easily in water
has a high boiling point
has a high melting point
conducts electricity when melted
Explanation:
Salts are ionic compounds. Ionic compounds are formed when two atoms exchange their valence electrons. One atom gains and the other atom loses.
Generally, ionic compounds have the following properties:
- They are usually hard solids with high melting points or liquids with high boiling points.
- They are soluble in water and insoluble in non-polar solvents. This is conforms with the solubility rule that like dissolve like.
- In aqueous solution or molten form, ionic compounds conducts electricity.
- They take part in very fast chemical reactions.
Learn more:
Ionic compounds brainly.com/question/6071838
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The answer would be c. Have you ever seen gravy? It always separates and leaves different layers.
Answer:
pH = 10.9
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to say that the undergoing reaction between this buffer and OH⁻ promotes the formation of more CO₃²⁻ because it acts as the base, we can do the following:
The resulting concentrations are:
![[CO_3^{2-}]=\frac{0.1435mol}{0.25L}=0.574M \\](https://tex.z-dn.net/?f=%5BCO_3%5E%7B2-%7D%5D%3D%5Cfrac%7B0.1435mol%7D%7B0.25L%7D%3D0.574M%20%5C%5C)
![[HCO_3^{-}]=\frac{0.0265mol}{0.25L}=0.106M](https://tex.z-dn.net/?f=%5BHCO_3%5E%7B-%7D%5D%3D%5Cfrac%7B0.0265mol%7D%7B0.25L%7D%3D0.106M)
Thus, since the pKa of this buffer system is 10.2, the change in the pH would be:
Which makes sense since basic OH⁻ ions were added.
Regards!
