Given yo = initial height the ball was thrown from.
Given vo = the initial velocity of the ball thrown
y = yo + (vo)t -16t^2 where t = time.
This is a parabola opening downward.
There is no y intercept as the ball is thrown upwards upwards not necessarily straight vertically.
The x-intercepts occur when the ball reaches the level the ball was thrown from or the ground.
I'm going to go with 4 I hope I'm right if it's wrong I'm sorry
Answer:
Step-by-step explanation:
Answer:
x = 1 y = -4
Step-by-step explanation:
- Plug the value of y into the other equation.
x + 3y = -11
x + 3(-4x) = -11
x - 12x = -11
-11x = -11
x = 1
- Now substitute the value of x into any equation.
y = -4x
y = -4(1)
y = -4
