We have:
![A=\left[\begin{array}{cc}3&-5\\4&1\end{array}\right]\qquad X=\left[\begin{array}{c}a\\b\end{array}\right]\qquad C=\left[\begin{array}{c}2\\10\end{array}\right]](https://tex.z-dn.net/?f=%20A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%26-5%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D%5Cqquad%20X%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Da%5C%5Cb%5Cend%7Barray%7D%5Cright%5D%5Cqquad%20C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
so:
![A\cdot X=C\\\\\\ \left[\begin{array}{cc}3&-5\\4&1\end{array}\right]\cdot\left[\begin{array}{c}a\\b\end{array}\right]=\left[\begin{array}{c}2\\10\end{array}\right]\\\\\\ \left[\begin{array}{c}3a-5b\\4a+1b\end{array}\right]=\left[\begin{array}{c}2\\10\end{array}\right]\\\\\\ \boxed{\begin{cases}3a-5b=2\\4a+b=10\end{cases}}](https://tex.z-dn.net/?f=A%5Ccdot%20X%3DC%5C%5C%5C%5C%5C%5C%0A%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%26-5%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Da%5C%5Cb%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C10%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C%0A%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3a-5b%5C%5C4a%2B1b%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C10%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B%5Cbegin%7Bcases%7D3a-5b%3D2%5C%5C4a%2Bb%3D10%5Cend%7Bcases%7D%7D)
And the solution of the system of equations:
OK........
X < 16
H0P3 It H3LPS :)
Plan B because you spending less then plan A
Answer:
(x+5)(x-3)
Step-by-step explanation:
We can factor the equation to be
(x+5)(x-3)
Answer:
Option C
Step-by-step explanation:
You need to begin by separating the shape into two distinct rectangles. The larger one has dimensions 15 cm * 8cm, while the smaller one has dimensions 7cm * 5cm. Adding these together, you get 15*8+7*5=155 square centimeters, or option C. Hope this helps!
