(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4
<span>(x^2 + 4)^2 + 32 = 12(x^2 + 4) </span>
<span>a^2 + 32 = 12a </span>
<span>a^2 - 12a + 32 = 0 </span>
<span>(a - 8)(a - 4) = 0 </span>
<span>a = 8 and a = 4 </span>
<span>for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 </span>
<span>for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 </span>
<span>x = -2, 0, +2 so your answer is going to be e
</span>
Answer:
Step-by-step explanation:
8,6,2, and 1
(2^6 / 8) * 1 = (64/8) * 1 = 8 * 1 = 8
Answer:
False
False
True
False
True
Step-by-step explanation:
I hope this helps!
Answer:
(x, y) = (-6, 3)
Step-by-step explanation:
Maybe you want to solve ...
Use the first equation to substitute for y in the second:
2x +3(-2x -9) = -3
2x -6x -27 = -3
-4x = 24 . . . . . . . . . add 27, simplify
x = -6 . . . . . . . . . . . divide by -4
y = -2(-6) -9 = 12 -9 = 3
The solution is (x, y) = (-6, 3).
Answer:
Step-by-step explanation:
6 + a
Putting value of a
6 + 3 = 9
5b
Putting value of b
5(2) = 10
C - 1
Putting value of c
12 - 1 = 11
