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Svetlanka [38]
2 years ago
9

How can you use fractions to place the decimal in the product?

Mathematics
1 answer:
Oxana [17]2 years ago
6 0

Answer:

it is easier to multiply first and then to place the decimal point. Multiply the factors as if they were whole numbers. Disregard the decimal point until you place it in the product.

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LOL 3 more to gooo . find the value of x
garri49 [273]

Answer:

17

Step-by-step explanation:

These two angles add up to 180, so we can set up an equation. 5x-23+7x-1=180. Now we combine like variables, getting 12x-23-1=180. We add 23 to both sides, and get 12x-1=203. Then we add 1 to both sides, getting 12x=204. Finally we divide by 12 on both sides, with our result as x=17.

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3 years ago
Leslie is a biologist. She is going to randomly select one animal from her lab to study. There are 5 salamanders, 3 crayfish, an
Scrat [10]
5/20 but if you were to simplify it then 1/4
8 0
3 years ago
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Reduce any fractions to lowest terms.Don’t round your answer, and don’t use mixed fractions
DENIUS [597]

Answer:

t < \frac{38}{17}

Step-by-step explanation:

Add '5t' to both sides

12t - 2 +5t < -5t +36 +5t

17t -2 < 36

Add ' 2' to both sides  

17t -2 +2 < 36 + 2

17t < 38

Dividing '17' on both sides

\frac{17t}{17} < \frac{38}{17}

4 0
3 years ago
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Plz help me!!!
Nadya [2.5K]
To solve this we are going to use the exponential function: f(t)=a(1(+/-)b)^t
where
f(t) is the final amount after t years
a is the initial amount
b is the decay  or grow rate rate in decimal form
t is the time in years

Expression A 
f(t)=624(0.95)^{4t}
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate b, we are going to use the formula: b=|1-base|*100%
b=|1-0.95|*100%
b=0.05*100%
b=5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at t=0
f(t)=624(0.95)^{4t}
f(0)=624(0.95)^{0t}
f(0)=624(0.95)^{0}
f(0)=624(1)
f(0)=624
We can conclude that the initial value of expression A is 624.

Expression B
f(t)=725(1.12)^{3t}
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
b=|1-base|*100%
b=|1-1.12|*100
b=|-0.12|*100%
b=0.12*100%
b=12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at t=0
f(t)=725(1.12)^{3t}
f(0)=725(1.12)^{0t}
f(0)=725(1.12)^{0}
f(0)=725(1)
f(0)=725
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months. 

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0
3 years ago
Simplify the expression by arranging the steps in sequence, based on the order of operations.
SSSSS [86.1K]

Answer:

Where is the question?

Step-by-step explanation:

5 0
3 years ago
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