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Luden [163]
2 years ago
9

Please help! Thank you!

Mathematics
2 answers:
Ne4ueva [31]2 years ago
5 0
Answer: 25a²b⁴c⁶
Hope this helps
serg [7]2 years ago
3 0
Simplified: 25a^2b^4c^5
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an NFL team kicker misses 2 out of every 11 field goals if he missed 8 filed goals throughout the season how many did he attempt
Aleks [24]
For this equation, you want to do it in fractions/ratios to properly solve it. You would have his average misses out of every field goal and his real missed attempts over total. It would look like this

\frac{2}{11}  =   \frac{8}{x}

You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:

(2)(x) = (8)(11)

From here you can get:

2x = 88

Divide each side by 2 to isolate x and you get:

x=  44

So he made a total of 44 field goals.
3 0
3 years ago
Read 2 more answers
Find the value of x, rounded to the nearest tenth. <br>a) 2.7<br>b) 4<br>c) 3.8<br>d) 2.9​
sertanlavr [38]
I Think The answer is a I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
4 0
3 years ago
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What’s the volume of 4.3ft 5.2ft cone round to nearest hundredth
Vika [28.1K]

Answer:

Pick the best solution.

Step-by-step explanation:

Volume of a cone is V = ⅓πr²h

If cone diameter is 4.3

V = ⅓π(4.3/2)²(5.2) = 25.17148... ≈ 25.17 ft³

If cone radius is 4.3

V = ⅓π(4.3)²(5.2) = 100.685950... ≈ 100.69 ft³

If cone diameter is 5.2

V = ⅓π(5.2/2)²(4.3) = 30.439938... ≈ 30.44 ft³

If cone radius is 5.2

V = ⅓π(5.2)²(4.3) = 121.75975... ≈ 121.76 ft³

5 0
3 years ago
Twins Isaac and Isaac where just born. Issac weighs 6 pounds 2 ounces and Isaiah weighs 5 pounds 4 ounces how many ounces do the
Ray Of Light [21]
182 ounces isthe answer
3 0
3 years ago
If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will
Serhud [2]

Answer:0.75 milligrams will  be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

3 0
3 years ago
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