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mestny [16]
3 years ago
8

Help me please! its a math question ​

Mathematics
2 answers:
Lisa [10]3 years ago
5 0
I think it would B also
ankoles [38]3 years ago
3 0
B would be your answer
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Find the size of angle xyz<br> give your answer to 3 significant figures
KengaRu [80]

Answer:

<u>68.2°</u>

Step-by-step explanation:

This is a right triangle, so we can use SIN,COS,TAN to solve for the angle.

We want ∠YXZ

THe side opposite to the angle is given as 20

The side adjacent to the angle is given as 8

Which trig ratio relates "opposite" and "adjacent"??

It is Tan!!

Thus, we can write:

Tan(\angle YXZ)=\frac{20}{8}\\Tan(\angle YXZ)=\frac{5}{2}\\Tan(\angle YXZ)=2.5\\\angle YXZ = ArcTan(2.5)\\\angle YXZ = 68.2

THis is the angle

<u>68.2°</u>

8 0
4 years ago
Please help me out with this
elena-14-01-66 [18.8K]

Answer:

FG=13

Step-by-step explanation:

We can make an equation that looks like this:

EF+FG=EG

Then, we can substitute in the numbers we know:

12+FG=25

Then solve:

FG=25-12

FG=13

Hope I helped soz if I'm wrong ouo.

~Potato.

Copyright Potato 2019.

Trademark ~Potato. 2019.

3 0
4 years ago
Read 2 more answers
Which variable is most efficient to isolate?
mezya [45]

y in the first equation because y is already by itself. All you have to do is move the -3x to the other side.

7 0
4 years ago
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How do you factor this? x^{2} + 5 x- 9 = ?
Oksanka [162]
x^2+5x-9\\\\a=1;\ b=5;\ c=-9\\\Delta=b^2-4ac\\\\\Delta=5^2-4\cdot1\cdot(-9)=25+36=61 > 0\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{61}\\\\x_1=\dfrac{-5-\sqrt{61}}{2\cdot1}=\dfrac{-5-\sqrt{61}}{2}\\\\x_2=\dfrac{-5+\sqrt{61}}{2\cdot1}=\dfrac{-5+\sqrt{61}}{2}\\\\x^2+5x-9=\left(x-\dfrac{-5-\sqrt{61}}{2}\right)\left(x-\dfrac{-5+\sqrt{61}}{2}\right)
6 0
3 years ago
Find the distance between the points:
lesantik [10]
To calculate distance between two points we use the distance formula sqrt((x2−x1)^2+(y2−y1)^2).  

To start, we find the square of the distance between x1 and x2 and y1 and y2.  The distance between x1 and x2, or 1 and 3, is 2. The distance between y1 and y2, or 3 and -4, is 7.

Now we square 2 and 7 and add them together to get 4 + 49 = 53.

The last thing we do to find the distance is take the square root of 53. 53 is not a perfect square and is also a prime number so our answer in simplest form is still sqrt53.<span />
6 0
3 years ago
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