50 points help please

A 9500 kg boxcar traveling at 14 m/s strikes a stationary second car. The two stick together and move off with a speed of 6.0 m/

jasenka [17]

<u>Answer:</u> The mass of the second car is 12666.7 kg

<u>Explanation:</u>

To calculate the mass of car, we use the equation of law of conservation of momentum, which is:

$m_1u_1+m_2u_2=(m_1+m_2)v$

where,

$m_1$ = mass of car 1 = 9500 kg

$u_1$ = Initial velocity of car 1 = 14 m/s

$m_2$ = mass of car 2 = ? kg

$u_2$ = Initial velocity of car 2 = 0 m/s

$v$ = Final velocity = 6.0 m/s

Putting values in above equation, we get:

$(9500\times 14)+(m_2\times 0)=(9500+m_2)6.0\\\\m_2=\frac{9500\times 14}{6}-9500=12666.7kg$

Hence, the mass of the second car is 12666.7 kg

6 0

4 years ago

According to Newton's second law, how are acceleration and mass related? Directly or indirectly when force is constant?

Aliun [14]

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

4 0

3 years ago

Which celestial body would have the strongest gravitational pull on a satellite orbiting 100km about its surface?

kodGreya [7K]

The body for which its

(Mass) / (radius squared)

is the greatest.

7 0

3 years ago

A generator connected to an RLC circuit has an rms voltage of 140 V and an rms current of 31 mA. Part A

vredina [299]

Answer:

53.06 ohm

Explanation:

We have given the rms voltage V =140 V

And the rms current i=31 mA

So the impedance $Z=\frac{V}{i}=\frac{140}{3\times 10^{-3}}=46.666kohm$

Resistance is given as R = 3 kohm

And capacitive reactance $X_C=6.5kohm$

We know that $Z=\sqrt{R^2+(X_L-X_C)^2}$

$46.666=\sqrt{3^2+(X_L-6.5)^2}$

Squaring both side $2177.1556=9+(X_L-6.5)^2$

$(X_L-6.5)^2=2168.155$

$(X_L-6.5)=46.5634$

$X_L=53.063ohm$

8 0

3 years ago

A mass moves back and forth in simple harmonic motion with amplitude A and period T.

Sever21 [200]

a. 0.5 T

- The amplitude A of a simple harmonic motion is the maximum displacement of the system with respect to the equilibrium position

- The period T is the time the system takes to complete one oscillation

During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.

So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion

$1 T : 4 A = t : 2 A$