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Brilliant_brown [7]
2 years ago
15

Can anybody write a short poem about friction

Physics
1 answer:
Luden [163]2 years ago
8 0
Answer:

you will be the clouds
and I will be the sky.
you will be the ocean
and I will be the shore.
you will be the trees
and I will be the wind.

whatever we are, you and I will always collide.

There you go! Let me know if it helped.
:)
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Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76
kicyunya [14]
If I’m understanding the question then 11.76cm^2 in two sig figs is 12cm^2. I don’t see a part c to this question though so if I’m not giving you the answer you need please advise and I will answer what you need! Thank you!!
8 0
4 years ago
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A thin film of cooking oil ( n = 1.47 ) is spread on a puddle of water ( n = 1.35 ) . What is the minimum thickness D min of the
zlopas [31]

Answer:

The minimum thickness of the oil is 77.55 nm

Explanation:

Given:

Refractive index of oil n_{o} = 1.47

Refractive index of water n_{w} = 1.35

Wavelength of light \lambda= 456 \times 10^{-9} m

From the equation of thin film interference,

The minimum thickness is given by,

    2n_{o} t = (n+\frac{1}{2}) \lambda

Where n = 0,1,2,3.........,t = thickness

Here we have to find minimum thickness so we use n = 0

     2n_{o} t  =( 0+\frac{1}{2} )\lambda

   t = \frac{\lambda }{4 n_{o} }

   t = \frac{456 \times 10^{-9} }{4 \times 1.47}

   t = 77.55 \times 10^{-9} m

   t  = 77.55 nm

Therefore, the minimum thickness of the oil is 77.55 nm

7 0
4 years ago
A van of mass 2500kg travelling at a velocity of 12 m/s collides with a stationary car of mass 700kg. The vehicles move together
Fiesta28 [93]

Answer: 9.375m/s

Explanation: This is an inelastic collision, so the formula is mv1+mv2=(m1+m2)v-final. My work is a follows:

2500kg(12m/s) + 700kg(0m/s)=(2500kg+700kg)(v-final)

30,000kg(m/s)+0=3200kg(v-final)

30,000kg(m/s)/3200kg=9.375m/s

5 0
3 years ago
4. A 70.0 kg boy and a 45.0 kg girl use an elastic rope while engaged in a tug-of-war on an icy,
marta [7]

Answer:

a_1 = 1.446m/s^2

Explanation:

Given

m_1 = 70.0kg -- Mass of the boy

m_2 = 45.0kg -- Mass of the girl

a_2 = 2.25m/s^2 -- Acceleration of the girl towards the boy

Required

Determine the acceleration of the boy towards the girl (a_1)

From the question, we understand that the surface is frictionless. This implies that the system is internal and the relationship between the given and required parameters is:

m_1 * a_1 = m_2 * a_2

Substitute values for m_1, m_2 and a_2

70.0 * a_1 = 45.0 * 2.25

Make a_1 the subject

\frac{70.0 * a_1}{70.0} = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{101.25}{70.0}

a_1 = 1.446m/s^2

<em>Hence, the acceleration of the boy towards the girl is 1.446m/s^2</em>

7 0
3 years ago
Which of the following is not a current use of radioisotopes?
andrey2020 [161]

Answer;

light fixtures

Explanation;

Radioactive isotopes have a variety of applications. They are useful because either we can detect their radioactivity or we can use the energy they release.

These uses includes;

  • Radioactive Dating; Radioactive isotopes are useful for establishing the ages of various objects.
  • Medical Applications; Radioactive isotopes have numerous medical applications; sterilization of equipment, diagnosing and treating illness and diseases.
  • Detection of leaks in building structures
  • Irradiation of Food; the radiation emitted by some radioactive substances can be used to kill microorganisms on a variety of foodstuffs, extending the shelf life of these products. etc.
5 0
4 years ago
Read 2 more answers
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