Answer:
35 glasses of classic milk tea
15 glasses of flavored milk tea
Step-by-step explanation:
You sold 50 glasses of classic and flavored milk tea.
c + f = 50
You made 4700 when classic tea costs 100 and flavored tea costs 80.
100c + 80f = 4700
Use this system of equation to solve. Use substitution. Rearrange the first equation so that it is equal to c. Then, plug the c-value into the second equation.
c + f = 50
c = 50 - f
100c + 80f = 4700
100(50 - f) + 80f = 4700
5000 - 100f + 80f = 4700
5000 - 20f = 4700
-20f = -300
f = 15
Plug the f-value into one of the equations and solve for c.
c + f = 50
c + 15 = 50
c = 35
35 glasses of classic milk tea and 15 glasses of flavored milk tea were sold.
Answer:
What are you supposed to do
Step-by-step explanation:
The equation that has the solution
is 3x^2 - 10x + 6 = 0
<h3>How to determine the equation?</h3>
The solution is given as:

The solution to a quadratic equation is

By comparing both equations, we have:
-b = 5
b^2 - 4ac = 7
2a = 3
Solve for b in -b = 5
b = -5
Solve for a in 2a = 3
a = 1.5
Substitute values for a and b in b^2 - 4ac = 7
(-5)^2 - 4 * 1.5c = 7
Evaluate
25 - 6c = 7
Subtract 25 from both sides
-6c = -18
Divide by - 6
c = 3
So, we have:
a = 1.5
b = -5
c = 3
A quadratic equation is represented as:
ax^2 + bx + c = 0
So, we have:
1.5x^2 - 5x +3 = 0
Multiply through by 2
3x^2 - 10x + 6 = 0
Hence, the equation that has the solution
is 3x^2 - 10x + 6 = 0
Read more about quadratic equation at:
brainly.com/question/1214333
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Answer:
<u>Given function</u>
#15 Find the inverse of h(x)
<u>Substitute x with y and h(x) with x and solve for y:</u>
- x = 2y - 1
- 2y = x + 1
- y = 1/2x + 1/2
<u>The inverse is:</u>
#16 The graph with both lines is attached.
The x- and y-intercepts of both functions have reversed values.
#17 Table of the inverse function will contain same numbers with swapped domain and range.
<u>Initial look is like this:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | | 0 | | 1 | | 2
<u>The rest of the table is filled in by finding the values:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | -0.5 | 0 | 0.5 | 1 | 1.5 | 2