Answer:
the probability that the average diameter of those sand dollars is more than 4.73 centimeters is 0.5910
Step-by-step explanation:
Given information:
mean, x = 5
standard deviation, σ = 0.9
number of sample, n = 16
now we calculate the probability that the average diameter of those sand dollars is more than 4.73 centimeters.
P(x>4.73) = P (z > (4.73 - x) / (σ
)
= P (z > (4.73 - 4) / (0.9
)
= P (z > 0.203)
= 0.5910
To solve this, we must set up a
Systems of Equations problem
Let's say
C stands for
Coach seats bought and
S stands for
sleeper cars bought
Here are our equations we have enough information to make.
c + s = 93 115c + 290s = $20,320 Lets solve for Coach seats first
To do that we need a value for s
In the first equation,
s = 93 - cLets plug that in for S in the second equation
115c + 290(93 - c) = $20,320 Distribute and simplify
115c + 26,970 - 290c = $20,320
Combine like terms
-175c + 26,970 = $20,320
-175c = -6650
divide
c =
c = 38We just found out 38 coach seats were bought.
Plug in 38 for C in this equation ⇒ 115c + 290s = $20,320 to find S
115(38) + 290s = $20,320 Distribute and Simplify
4,370 + 290s = $20,320
290s = $15,950
Divide
S =
S = 55We just completed the problem!
38 Coach seats were bought and 55 Sleeper car seats were bought.
Answer:
Step-by-step explanation:
speed = distance/time
so renaldo speed = 3.2/0.5 = 6.4miles/hr (since time taken is 1/2 hr)
now after 1 hr of his appoinment i.e at 5:30pm he took bus whose speed is same as before i.e 6.4 miles/hr
now time taken to cover this 4.8 miles = 4.8/6.4 = 3/4 hr (since time = distance /speed )
3/4 hr = 3/4 * 60 = 45 minutes
so he reached at 6:15pm . so he will be on time.