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2 years ago

Hello Friends Can Yall Plz Help Me For Brainliest Don’t Comments No B.S Yu Will Get Cursed out show ya work

Chemistry

1 answer:

VARVARA [1.3K]2 years ago

4 0

Answer:

it is b

Explanation:

mid ocean ridge diverges meaning it moving in two different direction horizontally - left to right

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Hydrogen sulfide and concentrated sulfuric acid react to form water and sulfur dioxide as shown in the following reaction:

Law Incorporation [45]

Answer:

2 moles of SO₂

Explanation:

Equation of reaction

H₂S + 3H₂SO₄ → 4H₂O + 4SO₂

From the equation of reaction above,

1 mole of H₂S will produce 4 moles of SO₂

1 mole of H₂S = 4 moles of SO₂

0.5moles of H₂S = zmoles of SO₂

z = (0.5*4) / 1

z = 2 moles of SO₂

0.5 moles of H₂S will produce 2 moles of SO₂

8 0

2 years ago

Cold packs, whose temperatures are lowered when ammonium nitrate dissolves in water, are carried by athletic trainers when trans

maksim [4K]

Answer:

d. ΔH° > 0, process is endothermic.

Explanation:

Cold packs contain ammonium nitrate (NH₄NO₃). When this salt dissolves in water, it decreases the temperature of the surroundings. This happens because the process is endothermic (absorbs heat from the surroundings). By convention, when a process is endothermic, the standard enthalpy carries a positive sign (ΔH° > 0).

6 0

2 years ago

When 8.30 mol Mg react with 13.5 mol HCI, what is the limiting reactant and how many moles of H2 can be formed?

vovikov84 [41]

6.75 moles of H₂

Explanation:

We have the following balanced chemical reaction:

Mg + 2 HCl → MgCl₂ + H₂

From the chemical reaction we deduce that if 1 mole of Mg is reating with 2 moles of HCl then 8.30 moles of Mg is reaction with 16.60 moles of HCl, quantity which is over our available 13.5 moles of HCl. The limiting reactant is HCl.

Knowing this we devise the following reasoning:

if 2 moles of HCl produces 1 mole of H₂

then 13.5 moles of HCl produces X moles of H₂

X = (13.5 × 1) / 2 = 6.75 moles of H₂

Learn more about:

balancing chemical equations

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4 0

3 years ago

18 An important environmental consideration is the appropriate disposal of cleaning solvents. An environmental waste treatment c

Katyanochek1 [597]

Answer:

a) Percentage by mass of carbon: 18.3%

Percentage by mass of hydrogen: 0.77%

b) Percentage by mass of chlorine: 80.37%

c) Molecular formula: $C_{2} H Cl_{3}$

Explanation:

Firstly, the mass of carbon must be determined by using a conversion factor:

$0.872g CO _{2} *\frac{12g C}{44g CO_{2} } = 0.238g CO_{2}$

The same process is used to calculate the amount of hydrogen:

$0.089g H_{2}O*\frac{2g H}{18g H_{2}O } = 0.010g H$

The percentage by mass of carbon and hydrogen are calculated as follows:

%C $\frac{0.238g}{1.3g} *100%$ = 18.3%

%H $\frac{0.010g}{1.3g} *100%$ =0.77%

From the precipation data it is possible obtain the amount of chlorine present in the compound:

$1.75 AgCl*\frac{35.45g Cl}{143.45g AgCl}$ = 0.43g AgCl

Let's calculate the percentage by mass of chlorine:

%Cl= $\frac{0.43g}{0.535g} * 100%$ = 80.37%

Assuming that we have 100g of the compound, it is possible to determine the number of moles of each element in the compound:

$18.3g C*\frac{1mol C}{12g C} = 1.52mol C$

$0.77g H*\frac{1mol H}{1g H} = 0.77mol H$

$80.37gCl*\frac{1molCl}{35.45g Cl} = 2.27mol Cl$

Dividing each of the quantities above by the smallest (0.77mol), the subscripts in a tentative formula would be

$C=\frac{1.52}{0.77} = 1.97$ ≈ 2

$H = \frac{0.77}{0.77} = 1$

$Cl =\frac{2.27}{0.77}=2.94$ ≈3

The empirical formula for the compound is:

$C_{2} H Cl_{3}$

The mass of this empirical formula is:

mass of C + mass of H + mass of Cl= 24g +1+ 106.35 =131.35g

This mass matches with the molar mass, which means that the supscript in the molecular formula are the same of the empirical one.

5 0

2 years ago

Calcium chloride forms an ionic solid. how are the particles held together and arranged in the solid

Advocard [28]

Calcium chloride forms an ionic compound with a regularly arranged lattice of oppositely charged ions.

The Na+ and Cl- ions are held together by strong electrostatic forces.

Hope that helps

7 0

2 years ago

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