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irga5000 [103]
3 years ago
8

Which of the following is a matter phase in which the molecules are arranged on a matrix and close together a. Gas b. Liquid c.

Solid d. All of these
Chemistry
2 answers:
Andrew [12]3 years ago
5 0

Solid! The molecules in solid matter are arranged closely together and packed quite tightly to maintain a regular shape. Hope this helps!

podryga [215]3 years ago
5 0

Answer: Option (c) is the correct answer.

Explanation:

It is known that in a solid, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial place but they can vibrate at their mean position.  

Hence, in solid substances the molecules have low kinetic energy.

On the other hand in liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

Whereas in gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

Hence, gases are able to expand more rapidly as compared to liquids.

Thus, we can conclude that out of the given options solid is a matter phase in which the molecules are arranged on a matrix and close together.

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3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
TiliK225 [7]

Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

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i assume that it would be a gametophyte.

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Hello, can someone pls help me ty!​
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