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Nataly [62]
3 years ago
9

I have 0.725 liters of a 1.500m solution of cacl2. How many grams of cacl2 are in the solution

Chemistry
1 answer:
Stella [2.4K]3 years ago
3 0

Answer:

120.7 g.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

<em>∴ M = (mass/molar mass)of NaCl/(V of the solution (L)).</em>

<em></em>

<em>∴ mass of CaCl₂ = (M)(V of the solution (L))(molar mass) </em>= (1.5 M)(0.725 L)(110.98 g/mol) = <em>120.7 g.</em>

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3 years ago
Explain the bonding that occurs between sodium and chlorine. Specifically, what kind of bonding takes
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ionic bond

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The theoretical yield of H₂S is 13.5 g.

The percent yield is 75.5 %.

<h3>What is the theoretical yield of H₂S from the reaction?</h3>

The equation of the reaction is given below:

  • FeS + 2 HCl → FeCl₂+ H₂S

Moles of FeS reacting = mass/molar mass

Molar mass of FeS = 88 g/mol

Moles of FeS reacting = 35/88 = 0.398 moles

Moles of H₂S produced = 0.398 moles

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Theoretical yield of H₂S is 13.5 g.

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Actual yield of H₂S = 10.2 g

Percent yield = 10.2/13.5 * 100%

Percent yield = 75.5 %

In conclusion, the actual yield is less than the theoretical yield.

Learn more about percent yield at: brainly.com/question/8638404

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