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denis-greek [22]
3 years ago
5

The governor of state A earns ​$48,980 more than the governor of state B. If the total of their salaries is ​$289,660​, find the

salaries of each
Mathematics
2 answers:
OLga [1]3 years ago
8 0

Answer:

Governor of State B: $120,340; Governor of State A: $169,320

Step-by-step explanation:

For the sake of this problem, let's set the salary of State B's governor as x. That would make the salary of State A's governor equal to x+48980. The following lists out how to solve this problem.

Governor B salary + Governor A salary = $48980

x+x+48980=289660

2x+48980=289660

2x=240680

x=120340

120340+48980=169320

Fed [463]3 years ago
8 0
Let x = salary for governor of state A
Let y = salary for governor of state B

Then x = y + 48980, since gov. of state A earns this much more than governor of state B.

Therefore we have x + y = 289660. Substitute for x.

(y + 48980) + y = 289660
2y + 48980 = 289660
2y = 240680
y = $120340, which is salary for governor B.

Now we substitute y into x = y + 48980
x = 120340 + 48980
x = $169320, which is salary for governor A.

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Maurinko [17]

Answer:

Mean waiting time = E(X) = 0 minute

Variance = Var(X) = 140

Step-by-step explanation:

f(x) = –3(25 – x²)/500 for –10 < x < +10

f(x) = (-75 + 3x²)/500 for -10 < x < 10

f(x) = (0.006x² - 0.15) for -10 < x < 10

a) The mean of a Probability distribution is given by its expected value

Mean = E(X) = Σ xᵢpᵢ

xᵢ = each variable In the sample space

pᵢ = probability of each variable In the sample space.

In integral terms,

E(X) = ∫ xf(x) dx (evaluating the integral all over the sample space; that is, for - 10 to 10)

E(X) = ∫¹⁰₋₁₀ xf(x) dx

E(X) = ∫¹⁰₋₁₀ x[0.006x² - 0.15] dx

E(X) = ∫¹⁰₋₁₀ [0.006x³ - 0.15x] dx

E(X) = [0.0015x⁴ - 0.075x²]¹⁰₋₁₀

E(X) = [0.0015(10⁴) - 0.075(10²)] - [0.0015(-10⁴) - 0.075(-10²)]

E(X) = [15 - 7.5] - [15 - 7.5] = 0 minutes

b) Variance is given as

Variance = Var(X) = Σx²p − μ²

where μ = mean = E(X)

In integral terms,

Var(X) = [∫¹⁰₋₁₀ x²f(x) dx] - μ²

∫¹⁰₋₁₀ x²f(x) dx = ∫¹⁰₋₁₀ x²(0.006x² - 0.15) dx

= ∫¹⁰₋₁₀ (0.006x⁴ - 0.15x²) dx

= [0.0012x⁵ - 0.05x³]¹⁰₋₁₀

= [0.0012(10⁵) - 0.05(10³)] - [0.0012(-10⁵) - 0.05(-10³)]

= [120 - 50] - [-120 + 50]

= 70 + 70 = 140

Var(X) = [∫¹⁰₋₁₀ x²f(x) dx] - μ²

Var(X) = 140 - 0² = 140.

Hope this Helps!!!

8 0
3 years ago
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Wittaler [7]

Answer:

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Step-by-step explanation:

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7 0
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