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3 years ago

Please help me find the value of x

Mathematics

2 answers:

Novay_Z [31]3 years ago

7 0

Set the equations to equal each other because the angles are equal.
8x - 63 = 4x - 27
+63 on both sides
8x = 4x + 36
-4x on both sides
4x = 36
/4 on both sides
x = 9

Answer:
x = 9

miskamm [114]3 years ago

7 0

Answer:

hhhhhhhhhhhhhhhhhhh

Step-by-step explanation:

x=9

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A teacher gave a 3-question multiple choice quiz. Each question had 4 choices to select from. If the a student completely guesse

goldenfox [79]

Answer:

0.9844

Step-by-step explanation:

This is a binomial probability problem.

Probability of getting a correct answer: p = 1/4

Probability of getting an incorrect answer: q = 3/4

Number of questions; n = 3

Thus;

probability of 2 or less correct answers is; P(x ≤ 2) = P(X = 2) + P(X = 1) + P(X = 0)

From binomial probability the formula is;

P(X = x) = C(n, x) × p^(x) × q^(n - x)

P(X = 2) = C(3, 2) × (¼)² × (¾)¹

P(X = 2) = 3 × 0.0625 × 0.75

P(X = 2) = 0.1406

P(X = 1) = C(3, 1) × (¼)¹ × (¾)²

P(X = 1) = 3 × 0.25 × 0.5625

P(X = 1) = 0.4219

P(X = 0) = C(3, 0) × (¼)^(0) × (¾)³

P(X = 0) = 0.4219

P(x ≤ 2) = 0.1406 + 0.4219 + 0.4219

P(x ≤ 2) = 0.9844

4 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

grandymaker [24]

Answer:

x=3

Step-by-step explanation:

I suggest getting this app called photo math, it will help you soo much.

3 0

3 years ago

Read 2 more answers

A farmer has two pieces of land in a parallelogram shape on the same base. He grows vegetables and flowers in two triangular pie

Hitman42 [59]

Step-by-step explanation:

In trapezoid ABCF, AB || CF.

Therefore, parallelograms ABEF & ABCD have same height and lie on the same base AB.

$\therefore Ar(\parallel^{gm} ABEF) = Ar(\parallel^{gm}ABCD)\\... (1)\\\\ \because\: Ar(\parallel^{gm} ABEF) \\=Ar(\triangle AFD) + Ar(\square \: ABED)....(2) \\\\\&\: Ar(\parallel^{gm}ABCD)\\= Ar(\triangle BCE) +Ar(\square ABED)....(3)$

From equations (1), (2) & (3), we find:

$Ar(\triangle AFD) + Ar(\square \: ABED) \\ = Ar(\triangle BCE) +Ar(\square ABED) \\ \\ \purple {\boxed {\therefore Ar(\triangle AFD) = Ar(\triangle BCE)}} \\$