Question

Please help me with this.And show all work as well ASAP!!​

Answer 1

Answer: The partial pressure of oxygen is 187 torr.

Explanation:

According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.

$p_1=x_1p_{total}$  

where, x = mole fraction  

$p_{total}$ = total pressure  

$x_{oxygen}=\frac{\text {moles of oxygen}}{\text {total moles}}$,  

$x_{oxygen}=\frac{3.0}{12.33}=0.243$,  

$p_{oxygen}=0.243\times 770torr=187torr$  

Thus the partial pressure of oxygen is 187 torr.