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Chemistry

1 answer:

qaws [65]3 years ago

6 0

Answer: The partial pressure of oxygen is 187 torr.

Explanation:

According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.

$p_1=x_1p_{total}$

where, x = mole fraction

$p_{total}$ = total pressure

$x_{oxygen}=\frac{\text {moles of oxygen}}{\text {total moles}}$ ,

$x_{oxygen}=\frac{3.0}{12.33}=0.243$ ,

$p_{oxygen}=0.243\times 770torr=187torr$

Thus the partial pressure of oxygen is 187 torr.

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1. The mass of 6.45 x 1022 atoms C

Fed [463]

Answer:

$\large \boxed{\text{1.29 g}}$

Explanation:

We must convert atoms of C to moles of C and then to grams of C.

1. Convert atoms to moles

$\text{Moles of C} = 6.45 \times10^{22}\text{ atoms C} \times \dfrac{\text{1 mol C}}{6.022 \times\ 10^{23} \text{ atoms C}} = \text{0.1071 mol C}$

2. Convert moles to grams

$\text{Mass of C} = \text{0.1071 mol C} \times \dfrac{\text{12.01 g C}}{\text{1 mol C}} = \text{1.29 g C}\\\text{The mass of C is $\large \boxed{\textbf{1.29 g}}$}$