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Serjik [45]
3 years ago
6

If you have an initial water level in a graduated cylinder of 15 mL and your

Chemistry
1 answer:
ki77a [65]3 years ago
3 0

Answer:

The answer is

<h2>0.5 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of aluminum = 2 g

volume = final volume of water - initial volume of water

volume = 19 - 15 = 4

volume = 4 mL

The density of the metal is

density =  \frac{2}{4}   =  \frac{1}{2}  \\

We have the final answer as

<h3>0.5 g/mL</h3>

Hope this helps you

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Consider the reaction: 2A(g)+B(g)→3C(g). When A is changing at a rate of -0.110M⋅s−1, How fast is C increasing?
mr_godi [17]
From the reaction above, the rate is given by the following formula:
r = -(1/2) dA / dt = - dB / dt = (1/3) dC/ dt
Note that A and B charge is negative due to they decrease with time
given dA / dt = -0.110 M/s
hence dB / dt = -0.110 / 2 = -0.055 M/s
dC / dt = (-3/2) (-0.110) = 0.165 M/s 
5 0
3 years ago
Calculate the area of a 3.0 inch by 5.0 inch index card in square millimeters (mm). (You can look up the formula for the area of
meriva

Answer:

The area of the given rectangular index card = <u>9677.4 mm²</u>    

Explanation:

Area is defined as the space occupied by a two dimensional shape or object. The SI unit of area is square metre (m²).

<u>The area of a rectangle</u> (A) =  length (l) × width (w)

Given dimensions of the rectangle: Length (l) = 5.0 inch, Width (w) = 3.0 inch

Since, 1 inch = 25.4 millimetres (mm)

Therefore, l = 5 × 25.4 = 127 mm, and w = 3 × 25.4 = 76.2 mm

Therefore, <u>the area of the given rectangular index card</u> = A= l × w = 127 mm × 76.2 mm = <u>9677.4 mm²</u>

5 0
3 years ago
Why does his teacher ask him to balance the equation by including the correct coefficients? to show that most molecules exist in
Ne4ueva [31]

Answer:

to show that atoms are conserved in chemical reactions

Explanation:

3 0
3 years ago
Read 2 more answers
A sample of gas at 30 degrees celcius occuoies 2.5 L at 1.3 atm. What volume will the sample occupyif pressure changes to 2 atm
Irina18 [472]

Answer: 1.73L

Explanation:Please see attachment for explanation

3 0
3 years ago
How many Joules of heat would be required
mote1985 [20]

Heat would be required  : 1,670 J

<h3>Further explanation</h3>

Given

mass of H₂O=5 g

Required

Heat to melt

Solution

The heat to change the phase can be formulated :

Q = m.Lf (melting/freezing)

Lf=latent heat of fusion

The heat of fusion for water at 0 °C : 334 J/g

Input given values in formula :

\tt Q=5\times 334=\boxed{\bold{1,670~J}}

4 0
3 years ago
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