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The answer as well as the explanation is in the image attached. Let me know if there's anything you're unable to see.
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A chemestretic equation equation which is formed by h20 mc square hydrogen peroxide and the equation of cf6c7bu7c
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Answer:
0.1410 M
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
The mole ratio of the acid, HCl (nA) = 1
The mole ratio of the base, NaOH (nB) = 1
Next, the data obtained from the question. This include:
Volume of acid, HCl (Va) = 25 mL
Volume of base, NaOH (Vb) = 34.55 mL
Concentration of base, NaOH (Cb) = 0.1020 M
Concentration of acid, HCl (Ca) =?
CaVa / CbVb = nA/nB
Ca × 25 / 0.1020 × 34.55 = 1/1
Ca × 25 / 3.5241 = 1/1
Cross multiply
Ca × 25 = 3.5241 × 1
Ca × 25 = 3.5241
Divide both side by 25
Ca = 3.5241 / 25
Ca = 0.1410 M
Therefore, the concentration of the acid, HCl is 0.1410 M
The formula of the given compounds are as follows:
a. copper (II) phosphate : Cu₃(PO₄)₂
b. phosphorus trichloride : PCl₃
c. potassium sulfite : K₂SO₃
d. strontium nitride : Sr₃N₂
e. nitrous acid : HNO₂
<h3>What is the formula of a compound?</h3>
The formula of a compound represents the compound using the symbol of the component elements in the compound showing the ratio in which the atoms of the elements combine in the compound.
The formula of the given compounds are as follows:
a. copper (II) phosphate : Cu₃(PO₄)₂
b. phosphorus trichloride : PCl₃
c. potassium sulfite : K₂SO₃
d. strontium nitride : Sr₃N₂
e. nitrous acid : HNO₂
In conclusion, the formula of a compound represents the compound with symbols.
Learn more about formula of compound at: brainly.com/question/13522594
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Answer:

Explanation:
Hello there!
In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:

In such a way, given the initial volume and both initial and final moles, we can easily compute the final volume as shown below:

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