Write a balanced equation for the dissolution of CaCO3? lable all phases too... So far I have CaCO3(aq)<-->Ca^2+(aq)+CO3^2
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Answer : The number of moles of produced will be, 0.241 moles.
Solution : Given,
Mass of Fe = 27.0 g
Molar mass of = 56 g/mole
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical reaction is,
From the reaction, we conclude that
As, 4 mole of react to give 2 mole of
So, 0.482 moles of react to give
moles of
Thus, the number of moles of produced will be, 0.241 moles.
