Answer:
6/(49π) ≈ 0.03898 m/min
Step-by-step explanation:
V = πr²h . . . . formula for the volume of a cylinder
dV/dt = πr²·dh/dt . . . . differentiate to find rate of change
Solving for dh/dt and filling in the numbers, we have ...
dh/dt = (dV/dt)/(πr²) = (6 m³/min)/(π(7 m)²) = 6/(49π) m/min
dh/dt ≈ 0.03898 m/min
Hello, do you know that for any a, b and c real numbers with c different from 0 the following is correct?
Then,
So,
Thank you.
Answer:
11. x=5
12. y= -1
13. m= -22
14. m=-4
15.n= 12, -4
16. x=6 ,-5
17. m=4
18. x= 3, -1
Step-by-step explanation:
I hope this help ;-)
Although they are the same variable, you cannot add two variables raised to different powers. 3x^1 + 5x^2 cannot work, but 3x^2 + 5x^2 can. Also, if you are multiplying them, they would combine to be 15x^3, as 3 and 5 (The coefficients) multiply together and x^2 times x^1 = x^3.
I hope that helps.
Answer:
75%
Step-by-step explanation:
try this answer
