A 120 -kg crate accelerates toward the positive x-direction . If the magnitude of the force due to friction is 74.4 N , what for
1 answer:
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To solve this problem we will apply the concept of current defined as the electron charge flow by the number of electrons per second. That is,
I = q*N
Here q is Flow of electric charge in one second and N the number of electron flow per second.
A the same time the power is described as the applied voltage for the current.
P = VI
We know the charge of electron, Coulombs, then the current is
And the power in the Beam is
Answer:
33.65°
Explanation:
radius, r = 53.1 m
m = 2.9 Mg = 2.9 x 10^6 g = 2900 kg
v = 67 km/h
convert km/h into m/s
v = 18.61 m/s
Let the angle of banking of road is θ, without friction
tan θ = 0.6655
θ = 33.65°
Thus, the angle of banking of road is 33.65°.
Answer:
The diameter of the moon's image is 0.31 cm.
Explanation:
Given that,
Focal length = 34.3 cm
Diameter of the moon
Mean distance from the earth
At that distance the object is assumes to be at infinity. hence the image will be formed at a distance equal to focal length
So, the image distance is 34.3 cm.
We need to calculate the diameter of the moon's image
Using formula of magnification
Hence, The diameter of the moon's image is 0.31 cm.