Answer:
The applied force to accelerate the crate is 374.4 N
Explanation:
Given;
mass of the crate, m = 120 kg
magnitude of force due to friction, Fk = 74.4N
acceleration of the crate, a = 2.5 m/s²
The net horizontal force on the crate is calculated as;
∑Fx = F - Fk
ma = F - Fk
F = ma + Fk
where;
F is the applied force to accelerate the crate by 2.5 m/s²
F = (120 x 2.5) + (74.4 N)
F = 300 N + 74.4 N
F = 374.4 N
Therefore, the applied force to accelerate the crate is 374.4 N
