Sodium Chloride could be classified as a salt.
When the planet is closest to the Sun, speed v and kinetic energy are the highest, and gravitational potential energy is the lowest. When the planet moves farther away, the speed and kinetic energy decrease, and the gravitational potential energy increases.
As the bright sun shines upon the water, the water slowly dissapears. This is an example of physical change because here the water is just transformed into water vapour. So only the state and the shape of the substance has changed. Its originality remains absolutely intact. In the second case where the same sunlight gives energy to the surrounding plants to convert water and carbon dioxide into sugar and oxygen gas, it is a chemical change. here new substances are formed and the identity of the original substances are lost.In chemical reactions, the mass of the product will always be the same as the mass of the reactants.
Answer:
Term 1 = (0.616 × 10⁻⁵)
Term 2 = (7.24 × 10⁻⁵)
Term 3 = (174 × 10⁻⁵)
Term 4 = (317 × 10⁻⁵)
(σ ₑ/ₘ) / (e/m) = (499 × 10⁻⁵) to the appropriate significant figures.
Explanation:
(σ ₑ/ₘ) / (e/m) = (σᵥ /V)² + (2 σᵢ/ɪ)² + (2 σʀ /R)² + (2 σᵣ /r)²
mean measurements
Voltage, V = (403 ± 1) V,
σᵥ = 1 V, V = 403 V
Current, I = (2.35 ± 0.01) A
σᵢ = 0.01 A, I = 2.35 A
Coils radius, R = (14.4 ± 0.3) cm
σʀ = 0.3 cm, R = 14.4 cm
Curvature of the electron trajectory, r = (7.1 ± 0.2) cm.
σᵣ = 0.2 cm, r = 7.1 cm
Term 1 = (σᵥ /V)² = (1/403)² = 0.0000061573 = (0.616 × 10⁻⁵)
Term 2 = (2 σᵢ/ɪ)² = (2×0.01/2.35)² = 0.000072431 = (7.24 × 10⁻⁵)
Term 3 = (2 σʀ /R)² = (2×0.3/14.4)² = 0.0017361111 = (174 × 10⁻⁵)
Term 4 = (2 σᵣ /r)² = (2×0.2/7.1)² = 0.0031739734 = (317 × 10⁻⁵)
The relative value of the e/m ratio is a sum of all the calculated terms.
(σ ₑ/ₘ) / (e/m)
= (0.616 + 7.24 + 174 + 317) × 10⁻⁵
= (498.856 × 10⁻⁵)
= (499 × 10⁻⁵) to the appropriate significant figures.
Hope this Helps!!!
Answer: E = 5.80*10^-13 J
Explanation:
Given
We use the law of conservation of momentum to solve this
Momentum before breakup = momentum after breakup
0 = m1v1 + m2v2
0 = 238m * -2.2*10^5 + 4m * v2
0 = -523.6m m/s + 4m * v2
v2 * 4m = 523.6m m/s
v2 = 523.6 m m/s / 4m
v2 = 130.9*10^5 m/s
v2 = 1.31*10^7 m/s
Using this speed in the energy equation, we have
E = 1/2m1v1² + 1/2m2v2²
E = 1/2 * (238 * 1.66*10^-27) * -2.2*10^5² + 1/2 * (4 * 1.66*10^-27) * 1.31*10^7²
E = [1/2 * 3.95*10^-25 * 4.84*10^10] + [1/2 * 6.64*10^-27 * 1.716*10^14]
E = (1/2 * 1.911*10^-14) + (1/2 * 1.139*10^-12)
E = 9.56*10^-15 + 5.7*10^-13
E = 5.80*10^-13 J
