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Svetllana [295]
3 years ago
9

Can someone please help me? Am I right? This is timed

Mathematics
1 answer:
il63 [147K]3 years ago
7 0
The correct answer would be 30 bc 40+20+10=70 which is 30 away from 100
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How to find the sector area
Reptile [31]
The sector area is = pi * r^2 (circumference/360). Do the work inside the () first and then multiply by pi r^2
7 0
4 years ago
1million got how many zeros?
Alexxandr [17]

Answer:

it would get 6 zeros

Step-by-step explanation:

hope it helps :)

6 0
3 years ago
If triangle ABC is dilated using a scale factor of 2, what will be the coordinates of A after the transformation
harkovskaia [24]

Answer:

A' = (-4,4)

Step-by-step explanation:

Given

A = (-2,2)    B = (1,3)       C = (1,0)

k =2 --- scale factor

Required

Determine A'

This is calculated as:

A' = A * k

A' = (-2,2) * 2

A' = (-2 * 2,2 * 2)

A' = (-4,4)

8 0
3 years ago
(30a^2 -11a+15)(5a-6)^-1
denis-greek [22]
(30a^2-11a+15)(5a-6)^{-1}= (30a^2-11a+15)/(5a-6)\(5a-6)(6a+5)/(5a-6)\6a+5

The final simplified answer is 6a + 5.
4 0
3 years ago
EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?
Black_prince [1.1K]

Answer:

(C) 10 units

Step-by-step explanation:

It is given that EFGH is a rhombus and EG = 16 and FH = 12.

We know that the diagonals of the rhombus are the perpendicular bisectors, therefore OF=6, OH=6, OE=8 and OG=8.

Now, using the Pythagoras theorem in ΔOFG, we have

(FG)^{2}=(OG)^{2}+(OF)^{2}

(FG)^{2}=(8)^{2}+(6)^{2}

(FG)^2=64+36

FG=\sqrt{100}

FG=10

Thus, the value of the side of the rhombus will be 10 units.

Hence, option C is correct.

3 0
4 years ago
Read 2 more answers
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