<span><span>1,867,866,560</span><span>1,867,866,560</span></span><span>.</span>
Y = kx where k is a constant
27 = k*9
k = 27/9 = 3
required variation is y = 3x
<span>1. 5564÷91
I know that 9 * 6 = 56
5564 rounds to 5600
91 rounds to 9
Since 56/9 = 6, then 5600/90 is the same as 560/9 = 60
The estimate is 60
2. </span><span>5391÷25
5391 sounds to 5400
25 is 1/4 of 100.
That means when you divide by 25, you can divide by 100 and multiply by 4.
5400/100 = 54
54 * 4 = 216
Estimate: 216
3. </span><span>explain how to estimate 498÷12
48/12 = 4
498 is little more than 480, so 498/12 is little more than 40
4. </span><span>which is the closest estimate for 2130÷ 33
A.7 B.17 C.70 D.700
2130/33
Round off the numerator and denominator to
2100/30
Reduce the fraction
210/3
Since I know that 21/3 = 7, then 210/3 = 70
Estimate: 70
</span>
Put the values you know in the formula and solve for the constant of variation.
.. y = kx^2
.. k = y/x^2 . . . . . fill in values for y and x and compute.
