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Svetach [21]
3 years ago
11

Why is hydrogen not used as fuel

Chemistry
2 answers:
meriva3 years ago
7 0

Answer:

so just like type anything right?

Explanation:

PIT_PIT [208]3 years ago
5 0

Answer: First, hydrogen is not as energy-dense as other fuels, meaning that you need a whole lot of it to do a little bit of work. ... Fuel cells are far more efficient than internal combustion engines, and a hydrogen fuel cell has cleaner emissions than an internal-combustion hydrogen engine.

Explanation:

You might be interested in
It is important to develop alternative<br> sources of energy because oil-
worty [1.4K]

Answer:

I don't know about the oil part but "It is important to develop alternative

sources of energy because scientists are unsure of how long they will last"

Explanation:

Because they are nonrenewable resources, it takes hundreds to millions of years for them to be made again naturally. Once we're out, we're out. It would be a huge issue of that happened because Oil, Petroleum, and Natural Gas (all fossil fuels) are needed for heating, gas stoves, etc.

4 0
3 years ago
A bicycle pump contains 250 mL of air at a pressure of 102 kPa. If the pump is
CaHeK987 [17]

Considering the Boyle's law, the new volume becomes 1,148,344.444 mL or 1148.34 L.

<h3>Boyle's law</h3>

Boyle's law relates pressure and volume, stating that the volume occupied by a given mass of gas at constant temperature is inversely proportional to pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following is true:

P1×V1=P2×V2

<h3>New volume</h3>

In this case, you know:

  • P1= 102 kPa= 10335.1 atm (being 1 kPa= 101.325 atm)
  • V1= 250 mL
  • P2= 2.25 atm
  • V2= ?

Replacing in the Boyle's law:

10335.1 atm ×250 mL= 2.25 atm×V2

Solving:

(10335.1 atm ×250 mL)÷ 2.25 atm= V2

<u><em>1,148,344.444 mL= 1148.34 L=  V2</em></u>

Finally, the new volume becomes 1,148,344.444 mL or 1148.34 L.

Learn more about Boyle's law:

brainly.com/question/4147359

#SPJ1

3 0
2 years ago
It is difficult to break the ionic bonds in a compound because of the...
mestny [16]

The answer to the first one is C. Strong attraction between ions

The answer to the second one is A. High melting points

Hope this helps :)

6 0
4 years ago
Read 2 more answers
A car travels 60 km in the first 2 hours and 68 km in the next 2 hours. What is the car’s average speed?
belka [17]
60+68=128
128/2=64 
so the answer is 64
I hope this helped

7 0
4 years ago
Read 2 more answers
The normal boiling point of ethanol (c2h5oh) is 78.3 °c and its molar enthalpy of vaporization is 38.56 kj/mol. what is the chan
kaheart [24]
When the entropy change of vaporization
       
 = enthalpy of vaporization/boiling point temperature 

when we have the enthalpy of vaporization = 38560 J/mol

and the boiling point temperature in Kelvin = 78.3 + 273 = 351.3 K

by substitution:

∴the entropy change of vaporization = 38560J/mol/351.3K

                                                               = 109.76 J/K/mol

and when the liquid has lesser entropy than the gas and we here convert from

gas to liquid so, the change in entropy = -109.76 J/K/mol

now, we need the moles of C2H5OH = mass/molar mass when the molar

mass of C2H5OH = 46 g/mol and mass = 42.2 g 

∴ moles of C2H5OH = 42.2 g / 46 g/mol = 0.92 moles

when 1 mol of C2H5OH turns in liquid entropy change →-109.76 J/K/mol

∴ 0.92 mol of C2H5OH → X

∴ X entropy change when 0.92 mol = -109.76 *0.92 mol / 1 mol

                                                             = 84.64 J/K


6 0
3 years ago
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