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Taya2010 [7]
4 years ago
10

Which monatomic ions would you expect radium (z = 88) and selenium (z = 34) to form?

Chemistry
2 answers:
makvit [3.9K]4 years ago
6 0

1) Radium will form Ra²⁺ ions, because it is metal with two valence electrons (7s²) and it will lost two electrons to have electric configuration like noble gas radon (Z=86).

Electroic configuration of radium atom:

₈₈Ra 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰4f¹⁴5s²5p⁶5d¹⁰6s²6p⁶7s².

2) Selenium wil form Se²⁻ ions, because it is nonmetal and it has six valence electrons (4s²4p⁴), it will gain two electrons to have electron configuration like noble gas krypton (Z=36).

Electronic configuration of selenium atom: ₃₄Se 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁴.

zhuklara [117]4 years ago
4 0
Radium belongs to 2nd group (Magnesium family) which means it will give +2 ion.
Ra2+

Selenium belongs to Oxygen family which means it will give -2 ion.
Se2-
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8 0
3 years ago
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 6.46 atm and 45°C in the reaction shown below?
ankoles [38]
The chemical reaction equation for this is 

XeF6 + 3H2 ---> Xe + 6HF

Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.

we get n = 0.1433 moles H2

to get the mass of XeF6, 

we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.

0.1433 moles H2 x \frac{1 mole XeF6}{3 moles H2} x \frac{245.28 g XeF6}{1 mole XeF6} = 11.71 g XeF6

Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.
3 0
4 years ago
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7 0
3 years ago
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