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borishaifa [10]
3 years ago
6

The concentration of hydroxide ions is greater than the concentration of hydronium ions for acidic solution. True or false.

Chemistry
1 answer:
larisa86 [58]3 years ago
5 0

Answer: False

Explanation:

An acid is defined as the substance which looses hydrogen ion or hydronium ions when dissolved in water.

A base is defined as the substance which looses hydroxide ions when dissolved in water.

If the solution has higher hydronium ion concentration as compared to the hydroxide ion concentration, then the pH will be low and the solution will be acidic.

If the solution has low hydronium ion concentration as compared to the hydroxide ion concentration then the pH will be high and the solution will be basic.

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If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first

<h3>What is EDTA ?</h3>

EDTA is a type of chemical which binds certain metal ions such as calcium and magnesium. some of the functions of EDTA  includes:

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The EDTA will readily react with metals which have a hiogher number of free ions that it can bind with.

Hence we can conclude that If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first.

Learn more about EDTA : brainly.com/question/10818175

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The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms
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Hydrogen mass is 1, the atom with mass number 7 is Lithium
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In the context of neurotransmitters, which of the following best describes the effect of norepinephrine stimulation?
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How many naturally occurring elements are there
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4 0
3 years ago
A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to reach the
RSB [31]

Answer:

The concentration of the borax solution is 0.1066 M

Explanation:

Step 1: Dtaa given

Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L

Molarity of H2SO4  = 1.03 M

Volume of the H2SO4 = 2.07 mL = 0.00207 L

Step 2: The balanced equation

Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O

Step 3: Calculate molarity of borax solution

b*Ca*Va = a * Cb*Vb

⇒with B = the coefficient of H2SO4 = 1

⇒with Ca = the concentration of borax = TO BE DETERMINED

⇒with Va = the volume of borax = 0.020 L

⇒with a = the coefficient of borax = 1

⇒with Cb = the concentration of H2SO4 = 1.03 M

⇒with Vb = the volume of H2SO4 = 0.00207 L

Ca*0.020 L = 1.03 M * 0.00207 L

Ca = (1.03 * 0.00207) / 0.020

Ca = 0.1066 M

The concentration of the borax solution is 0.1066 M

6 0
3 years ago
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