We can use the formula P=IV to calculate the current, where “P” is power (measured in watts), “I” is current (measured in Amps), and “V” is voltage. Simply plug and solve:
P = IV
(3.5 Watts) = I(120 volts)
I = 0.0292 Amps
The current flowing through the bulb is approximately 0.0292 Amps.
Hope this helps!
Hey there!
Static electricity is a missing charge. When positive ions are formed (where an electron is missing), this imbalance is called static electricity.
Answer:
A
Explanation:
The dissolving process depends on the interaction between solute and solvent (solvation) and the breaking up of the intermolecular bond between solutes. The former is exothermic in nature, while the later is endothermic. Energy is released when solute-solvent particles interact. When this energy exceeds the energy required to break intermolecular bonds between the solute particles, dissolution is exothermic.
Answer : To determine enthalpy of solution for a solid with δH values.
One can use the equation as H (reaction) = H (products) - H (reactants)
If δH values are known one can simply substitute them in the above equation and get the enthalpy of the required solution.
Answer:
1A: ns^1
2A: ns^2
5A: ns^2np^3
7A: ns^2np^5
Explanation:
<u>According to IUPAC, the columns 1A, 2A, 5A, and 7A correspond to the groups, 1, 2, 15 and 17, respectively</u>.
The outer electron configuration of these columns are the following:
Column Outer electron configuration
1A ns^1
2A ns^2
5A ns^2np^3
7A ns^2np^5
Therefore, for the column 1A the s orbital has only one electron, for the column 2A has the s orbital completed with 2 electrons, for the column 5A the number of electrons in the s orbital is complete (2) and the number of electrons in the p orbital is 3, for the column 7A the s orbital has 2 electrons and the p orbital has 5 electrons.
I hope it helps you!
