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BigorU [14]
3 years ago
14

1. Translate the variable expression into a word phrase: 4b – 2

Mathematics
2 answers:
nevsk [136]3 years ago
7 0
1. 4b - 2 : the product of 4 and a number (b) decreased by 2

2. the sum of 15 and 4 times a number......15 + 4x

3. 8 fewer boys then girls...how many boys.......b = g - 8

4. It will be less then 1 because of the negative exponent....a negative exponent will mean the number is less then 1...I dont really know how else to explain it.

5. Doug is twice Anna's age...doug is 34 years old
   I dont know the 5 step plan...but I am putting what I do know

   d = doug's age
   a = anna's age
   
   d = 2a
   d = 34
   
   34 = 2a
   34/2 = a
   17 = a....so anna is 17

   check..
   d = 2a
   d = 2(17)
    d = 34 (correct)
svetlana [45]3 years ago
7 0

Answer:

1) The difference between four times the number b and 2.

2) 16 + 4*x

3) if there are 8 fewer boys than girls in the class, then g - b = 8, so the number of boys is: b = g - 8

4) 3.2*10^{-4} is less than 1 because of the negative exponent, the expression is equivalent to 3.2/10000 = 0.00032 < 1

5) Ok, Dough is twice Anne's age. so if D is Dough's age, and A is Anne's age:

D = 2*A

and D = 34

then 34 = 2*A

if we divide both sides by 2, we get

34/2 = 2*A/2

17 = A

Anne is 17 years old.

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sesenic [268]

Answer:

Option (B)

Step-by-step explanation:

Given sequence is 45, 135, 405, 1215, 3645..........

Since it's a geometric sequence,

Common ratio of each successive term to the previous term

r = \frac{135}{45}=3

First term of the sequence 'a' = 45

Explicit formula of a geometric sequence will be,

a_n=a(r)^{n-1}

a_n=45(3)^{n-1}

Recursive formula of this sequence will be,

a_n=3(a_{n-1}), a_1=45

Therefore, Option (B) will be the answer.

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xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

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Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

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Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

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Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

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