Determine the empirical formula of a compound that was found to contain 6.412 g potassium, 2.292 g n, and 7.871 g o.
1 answer:
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Answer : The correct option is, (d) sublimation of dry ice.
Explanation :
Entropy : It is defined as the measurement of randomness or disorderedness in a system.
The order of entropy will be,
As we are moving from solid state to liquid state to gaseous state, the entropy will be increases due to the increase in the disorderedness.
As we are moving from gaseous state to liquid state to solid state, the entropy will be decreases due to the decrease in the disorderedness.
(a) Condensation of steam.
Condensation : It is a type of process in which the phase changes from gaseous state to liquid state at constant temperature.
In this process, phase changes from gaseous state to liquid state that means the degree of disorderedness decreases. So, the entropy will also decreases.
(b) Reaction of magnesium with oxygen to form magnesium oxide.
In this reaction, the randomness of reactant molecules are more (solid+gas) and as we move towards the formation of product the randomness become less (solid) that means the degree of disorderedness decreases. So, the entropy will also decreases.
(d) Reaction of nitrogen and hydrogen to form ammonia.
In this reaction, the randomness of reactant molecules are more (2 moles of gas) and as we move towards the formation of product the randomness become less (1 mole of gas) that means the degree of disorderedness decreases. So, the entropy will also decreases.
(d) Sublimation of dry ice.
Sublimation : It is a type of process in which the phase changes from solid state to gaseous state without passing through the liquid state at constant temperature.
In this process, phase changes from solid state to gaseous state that means the degree of disorderedness increases. So, the entropy will also increases.
Empirical formula: MoO3
Answer:
1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.
2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.
Explanation:
The molecular formula of boron trifluoride is .
So, one mole of boron trifluoride has one mole of boron atoms.
1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.
The number of atoms in 2.20 moles of boron is:
One mole of boron has ---- atoms.
Then, 2.20 moles of boron has
-
2. Calculate the number of moles of BF3 in 5.35*1022 molecules.
One mole of boron trifluoride has three moles of fluorine atoms.
Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.
=0.266mol of fluorine atoms.