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posledela
3 years ago
10

What was the scientific basis for the unit amu

Chemistry
1 answer:
Naya [18.7K]3 years ago
4 0
Natural abundance of oxygen I think
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What is the concentration of a dextrose solution prepared by diluting 16 mL of a 1.0 M dextrose solution to 25 mL using a 25 mL
seraphim [82]

Answer:

0.64 M

Explanation:

Step 1: Given data

  • Initial concentration (C₁): 1.0 M
  • Initial volume (V₁): 16 mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 25 mL

Step 2: Calculate the final concentration of the dextrose solution

We want to prepare a diluted solution from a concentrated one. We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 1.0 M × 16 mL / 25 mL

C₂ = 0.64 M

4 0
3 years ago
Hydrogen peroxide is a liquid that decomposes to form oxygen gas and
ehidna [41]
A would be the answer to this question
6 0
2 years ago
Which of the following statements is true?
Dovator [93]

Answer:

c

Explanation: c

8 0
3 years ago
Read 2 more answers
If the total population of Asian women was 5000in the 2008 how many females suffered a stroke?
Finger [1]

Answer:

Hi there!

I believe you are missing an attachment to this question however

I strongly believe that the answer you are looking for is 85.

Explanation:

If you provide the graph, the rate of strokes in Asian women will be 17 per 1,000 women so all you have to do is multiply 17 by 5 and you get 85

4 0
3 years ago
Even though we have known of many nuclear energy technologies for about one century some of these technologies have not yet been
Romashka [77]

<u>Answer:</u> The nuclear fission reaction of U-234.043 is written below.

<u>Explanation:</u>

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

^{234.043}_{92}\textrm{U}\rightarrow ^{137.159}_{54}\textrm{Xe}+^{A}_{38}\textrm{Sr}+3^{1.0087}_0\textrm{n}+180MeV

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

234.043 = 137.159 + A + 3(1.0087)

A = 93.858

Now, the chemical equation becomes:

^{234.043}_{92}\textrm{U}\rightarrow ^{137.159}_{54}\textrm{Xe}+^{93.858}_{38}\textrm{Sr}+3^{1.0087}_0\textrm{n}+180MeV

Hence, the nuclear fission reaction of U-234.043 is written above.

7 0
3 years ago
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