Answer:
5.96 g/cm^3
Explanation:
Corner atom = 1/8
Atoms in center = 1
Atoms in face of the cube= 1/2
Molar mass of V = 50.94 g/mol <em>(from period table)</em>
1 mole = 6.02x10^23
<em>In BCC unit cell:</em>
(8 x 1/8)+ 1=2 per 1 unit cell
<em>Mass: </em>2(50.94g)/6.02x10^23 = 1.69x10^-22 g/unit cell
305pm=(305x10^-12m÷10^-2m) x (1mL÷1cm^3)
= 2.837 x 10^-23 mL
<em>1pm=10^-12m</em>
<em>1cm=10^-2m</em>
<em>1mL=1cm^3</em>
<em></em>
density=mass/volume
density of V = 1.69x10^-22g÷2.837x10^-23mL
=5.957g/mL
=5.96g/cm^3
Explanation:
protons, neutrons and electrons
1.08 atm is the pressure for a certain tire in atmosphere.
<u>Explanation:</u>
One kilo pascal (1 kPa) corresponds to 1000 pascal. Another common unit used for pressure is atmosphere (symbolised as ‘atm’). 1 atm refers the standard atmospheric pressures and corresponds to 760 mm Hg and 101.3 kPa. Atmospheric pressures are commonly referred as square inches (psi)/ pounds.
![1 \mathrm{atm}=101.3 \mathrm{kPa}=101,325 \mathrm{Pa}=760 \mathrm{mm} \mathrm{Hg}=760 \text { torr }=14.7 \mathrm{lb} / \mathrm{in}^{2}(\mathrm{psi})](https://tex.z-dn.net/?f=1%20%5Cmathrm%7Batm%7D%3D101.3%20%5Cmathrm%7BkPa%7D%3D101%2C325%20%5Cmathrm%7BPa%7D%3D760%20%5Cmathrm%7Bmm%7D%20%5Cmathrm%7BHg%7D%3D760%20%5Ctext%20%7B%20torr%20%7D%3D14.7%20%5Cmathrm%7Blb%7D%20%2F%20%5Cmathrm%7Bin%7D%5E%7B2%7D%28%5Cmathrm%7Bpsi%7D%29)
Given:
The air pressure for a certain tire = 109 kPa
We need to find pressure in atmospheres
So, we know,
1 atm = 101.3 kPa
Hence,
![\frac{109 \mathrm{kPa}}{1} \times \frac{1 \mathrm{atm}}{101.3 \mathrm{kPa}}=1.076=1.08 \mathrm{atm}](https://tex.z-dn.net/?f=%5Cfrac%7B109%20%5Cmathrm%7BkPa%7D%7D%7B1%7D%20%5Ctimes%20%5Cfrac%7B1%20%5Cmathrm%7Batm%7D%7D%7B101.3%20%5Cmathrm%7BkPa%7D%7D%3D1.076%3D1.08%20%5Cmathrm%7Batm%7D)
1.08 atm is the pressure for a certain tire in atmosphere.
A central silicon atom is bonded to two chlorine atoms and two methyl groups
Explanation:
Enantiomers are chiral molecules that are mirror images of each other but cannot be superimposed on each other. In this case, a silicon atom, bonded to two chlorine atoms and two methyl groups, when its bonds are rotated, can appear like mirror images of the previous molecule.