All categories

2 years ago

According to the following reaction, how many moles of hydrobromic acid are necessary to form 0.274 moles bromine?

Chemistry

1 answer:

Naily [24]2 years ago

8 0

Answer:

0.548 moles of HBr are required

Explanation:

Given data:

Number of moles of hydrobromic acid = ?

Moles of bromine formed = 0.274 mol

Solution:

Chemical equation:

2HBr → H₂ + Br₂

Now we will compare the moles of HBr with Br₂.

Br₂ : HBr

1 : 2

0.274 : 2×0.274=0.548

Thus, 0.548 moles of HBr are required.

You might be interested in

A stock solution is made by dissolving 66.05 g of (NH4)2SO4 in enough water to make 250 mL of solution. A 10.0 mL sample of this

Degger [83]

If the solute is properly distributed in the given volume, there are 2.642 g of (NH4)2SO4 per 10 mL. For the new solution, divide the 2.642 g by the molar mass of the compound. The answer is 0.02 moles. Then, divide this by the new volume, 50 mL or 0.05 L. The concentration of the new solution is 0.4 M.

7 0

3 years ago

Read 2 more answers

The Lewis dot notation for two atoms is shown.

NISA [10]

To help, I drew a diagram. This represents an ionic bond between Na and Cl. Na is giving his single electron to Cl, which is indicated by the arrow, to make Cl full with 8 electrons.

7 0

3 years ago

Read 2 more answers

What are the names of the products in the chemical equation shown below

ANTONII [103]

There’s nothing there... send me a message and I’ll help but there is nothing there

7 0

3 years ago

Read 2 more answers

A 17.9 mL sample of a 0.445 M aqueous hypochlorous acid solution is titrated with a 0.374 M aqueous sodium hydroxide solution. W

In-s [12.5K]

Answer:

the pH at the start of the titration is 3

4 0

3 years ago

Please help me with this basic organic conversion.<br>use the shortest way to do it

jonny [76]

Answer:

See explanation

Explanation:

This conversion must go through a sequence of steps as i have shown in the image attached to this answer.

The acetone is converted to propan-2-ol using LiAlH4, THF and acid. The propan-2-ol may be converted to propene by E2 elimination. Addition of HBr yields 2-bromo propane.

The Wurtz reaction converts 2-bromo propane to 2,3- dimethyl butane. This can be brominated in the presence of light to yield 3-bromo-2,3-dimethyl butane. Elimination of HBr using a base leads to the formation of the required product as shown.

7 0

3 years ago